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  1. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    I have a question if the force was worked out to be 3.05 newtons to lift the weight up in 1 second but the rotation of the cam took 0.25sec with a torque of 0.053Nm will that still lift the weight? thanks and whats gaslighting I need to lift the weight in 0.25 seconds does this affect the torque...
  2. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    It looks like you're looking at the size of the number and not following the math of how they were derived or what they mean and stand for! thanks
  3. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    started the working from the beggining theres a couple of little creases to iron out but it's going well I'm going to put together a PDF file explaining from beggining to end, thanks
  4. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    now need to add in losses for realism
  5. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    so I've found that if the speed of the input gear is 3.3874322rad/sec and the output speed is 8pi and the output torque is 0.053Nm then the input torque is 0.3932Nm and the Gr is 1 : 7.4196 now I need to design a compound gear -0.3932Nm/10.8(the inertia)= negative acceleration...
  6. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    so I want to relate the speed of the wheel which is 3.3873422 rad/sec to that of the cam, I want the cam to rotate once in 0.25 seconds which is 8 rad/sec if the gear on the flywheel is 0.01m then velocity equals 0.033873422m/s tangientially add compound gear so that the smaller is meshed with...
  7. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    so I think I know what you're saying the torque at the tip of the cam before it drops needs a slight increase in torque and if I made that the torque on the input then it would be sufficient to turn through the entire angle 2pi rad
  8. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    consider the spiral has an average radius Ravg half way between the minimum and maximum radii Rmin, Rmax. The spiral length would then be 2 x pi x Ravg. Over that length the cam-follower moves a vertical distance Rmax - Rmin. So, the average slope is (Rmax-Rmin)/(2 x pi x Ravg). The rotational...
  9. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    ok how do you do that, could you do the calculation so I can see where I went wrong please? can you clarify that the answer is 0.0369Nm so I used the chatgpt and entered the variables and it confirms the torque of 0.03696Nm
  10. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    my result is different to yours Mr Alec_t
  11. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    I have a snail shell drop cam who's larger radius is 0.126m and minimum radius 0.05m I want it to rotate and push up on a follower with 3.05Newtons the cam turns through angle 2pi rad before resetting I need to know the torque I need to produce this motion in 0.25seconds Step 1: Calculate the...
  12. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    just for my understanding can you eplain wih arbitrary numbers, or even the numbers im working with Rmin=0.05m Rmax=0.126m also if it was designed for using Rmax instead of ravg then that would over compensate and therefore be enough if that makes any sense, thanks I think this is a question...
  13. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    tried it, believe it or not I've been getting this error on certain sites since I've had my connexion kinda just gotten used to it although you given me a few more options to explore I think I've spent enough time trying to fix it and geting on with it regardless but again thank you for the time...
  14. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    Is there an imparticular book you think I should buy?
  15. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    I'm not an expert but it's something to do with the certificates and actual time
  16. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    but its the same across firefox opera explorer and brave and chrome
  17. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    thanks bertus but it's not having it, so, back to the subject matter the cam/scissor/flywheel torque, torque needed to get 3.05N out of the cam at the furthest from the axis please
  18. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    I think the time setting is fudging it the clock wont set!!
  19. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    same thing
  20. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    so the torque into the cam is positive but the same torque is negative from the flywheel and negative torque/inertia of the flywheel gives decceleration I need to find the torque required to give a force of 3.05N at the top of the snail/drop of cam and this torque will be efficient enough...
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