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  1. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    so this is the settings box
  2. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    so the NET Force need to be 3.05Newton that's because the cam will deccelerate the flywheel over the time it takes to lift the weight
  3. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    ok cool thank you for clarification Mr Alec_t
  4. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    this might sound stupid but if the forces are in equilibrium (downwards force 2.7N and upward force from the edge of the cam 2.7N) how/why will the scissor/cam mechanism move the weight upwards at the pivot? can someone explain please, thanks so I had a look around and found that I do...
  5. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    short answer, no, nice browser though and I'm glad you tried to help me out!
  6. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    never heard of brave; installing as we speak
  7. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    my internet blocks allsorts
  8. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    I understand that something will stay at rest or in uniform motion unless acted upon by an outside force and the forces are balanced but a little confused!
  9. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    thanks Mr bertus! my internet does not allow for that site
  10. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    this might sound stupid but if the forces are in equilibreum (downwars force 2.7N and upward force from the edge of the cam 2.7N) how/why will the scissor/cam mechanism move the weight upwards?
  11. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    ok cheers mate got a book on mechanisms and related math on monday too
  12. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    okay cool thanks, can you provide a comprehensive site or info on cams please and thanks again for your insight
  13. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    ok such as is done with a screw mechanism in a vehicle scissor jack. I understand now if it was not from the horizontal the the weight of the car is going down and that would be the weight force of the car downward and would be like lifting it directly if the load is 2.7N (2753233775kg /...
  14. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    ok I misunderstood nonetheless if I moved an upward force up at that pivot, a distance dy, then at stage 4 then it would have moved 4*dy. And is it true when I said if the cam's max distance from the axis of rotation is 0.126 the and has 10 levels then the top of the scissor will have moved...
  15. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    It might not even need acceleration the motion upwards could be a constant velocity with the force being the same as the downward load of 2.7N yep I need a nudge in the right direction with this, thanks
  16. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    can anyone point me to a page or pdf that explains the math of the snail cam mechanism ie torques, radial force, power, time etc the way I see it is a rotational ramp incline
  17. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    forgive me, I don't understand!?!
  18. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    modify the force for upward acceleration so that it accelerates at 1.26m/sec^2 Ftot = Fgrav + Facc 3.05N so the weight would lift in 1 second with this force applied! so because the cam moves the pivot on the 10th level it need to push with 10 times the force = 30.5N now not too sure how to work...
  19. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    so if the snail shell cam max radius is 0.12m and the radius of the thinest part of the cams radius is 0.05m spiraling outward then I would need 10 levels of scissor linkage, because the furthest radius on the cams axis is 0.12m one rotation of the cam would lift the 0.275kg weight up to the top...
  20. Maglatron

    I want to know all of the maths concerning this scissor mechanism!

    F = m g gravitaional force, weight mass m (0.2753233775 kg) g acceleration due to gravity 9.80665m/sec^2 Fgrav = 2.7N force for upward acceleration F = m a m = (0.2753233775 kg) a = 1m/sec^2 (arbitrary acceleration) Facc = is just 0.2753233775N total force required Ftot = Fgrav+Facc...
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