for the 9 volt at the beggining I will use a voltage divider Vout = Vin x (R2/R1+R2)
pick R1 to be 10k
9V = 12V x (R2/10k+R2)
solve for R2 = (9V x 10k/12V-9V)
R2 = 90k/3V
R2 approximatly 30k!
It's like if I know how it's supposed to look and know why it works that way, then I can understand it, but trying to figure it out on my own is like putting together a puzzle without a picture on it! so please provide me with the images I need, cheers
please can you draw the schematic so I can work it out looking at the correct configuration because I don't understand, I'm lost, I need an image of the circuit running off a 12v source please please please can you do a design of the cascaded bar type LM3914 with the REF virtual ground from the...
I get why the REF virtual ground is put to the Rlo, it's because 6v is the lowest instead of 0v and the upper limit is between 6v and 12v I just don't know how to set it up
bertus, I feel you understand the problem a little better, can you shed any more light on this matter please? if im supplying Rlo with the reference ground from the the buffer circuit, how do I set the Rhi value to say, 9V? cheers
I think you missed a bit, I am going to be connecting the Rlo to the REF virtual ground of the buffer wich is 6V, and the -V will be connected to ground, Rhi should be between this REF voltage (6V) and +12V so I choose (9V), how do you wire it??
I've read the stuff on LM3914 how would I hook this up if I connected the pin 4 Rlo to REF of the buffer circuit how would I set the Rhi to be inbetween the REF and +12v
I don't understand what you just said but thanks for the link mr prime I want to know how do you make the voltage on Rhi between REF and +12V, resistors?? I will read the entire article and if I still don't understand I'll check back looks like good info, cheers