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- Nov 17, 2011
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- 14,271
Look closely at the circuit. All resistors are connected to tha same voltage source. What voltage do they see?
The problem with your math is here:
3/2 = V1/6
I assume that 3/2 means 3V (from the source)/2Ohm (total parallel resistance).
But V1/6 is only the current through the 6 Ohm resistor, not the total current. Look up kirchhoffs laws and apply the rule for the sum ot all currents flowing in and out of a node to your circuit.
If still unsure: think of the electric power in your house: how are the lamps connected to the system?
Imagine having a single lamp. What happens, if you connect a second lamp in parallel? Does the brightness change?
What happens, if you add the second lamp in series instead?
Post your results, I will check them.
Harald
The problem with your math is here:
3/2 = V1/6
I assume that 3/2 means 3V (from the source)/2Ohm (total parallel resistance).
But V1/6 is only the current through the 6 Ohm resistor, not the total current. Look up kirchhoffs laws and apply the rule for the sum ot all currents flowing in and out of a node to your circuit.
If still unsure: think of the electric power in your house: how are the lamps connected to the system?
Imagine having a single lamp. What happens, if you connect a second lamp in parallel? Does the brightness change?
What happens, if you add the second lamp in series instead?
Post your results, I will check them.
Harald
