J
Joerg
- Jan 1, 1970
- 0
Terry said:Jamie said:MooseFET said:MooseFET wrote:
MooseFET wrote:
Terry Given wrote:
Jamie Morken wrote:
MooseFET wrote:
Joerg wrote:
MooseFET wrote:
[...]
To monitor the waveform? Why not just sample it? Send
sampling
pulse
through toroid xfmr,
[....]
I cant quite picture it, would you care to cough up an ascii
schematic?
didnt unitrode make a chipset that did prettty much this?
Here's what was rattling through my mind while I was thinking
about
how to do this.
ACFB+ ! ! ACFB-
+-/\/\--+
! !
(((((((
=======
(((((((
! ! !
! -- ! ---------+--/\/\/----
+Vout
! ! !
!/ \! \
!! ----------! !---- /
Drive ---- !! ( !\e e/! ! \
) !! ( ! ! ! !
) !! ------------+-------+----- ! --+-----------
-Vout
) !! ( !
GND ------ !! ( !
!! ---------------------------
This works even in the AC case if the resistors bring the
voltage low
enough that the EB junctions aren't breaking down while the
transistors trade off conducting.
Hi,
I put this schematic into ltspice and it seems to kind of
work, the AC
voltage is being chopped by the Drive signal to Vout, but it
is 90
degrees out of phase with the input AC signal, and also very low
amplitude. Any ideas how to get the output phase to match the
AC input?
Heres the circuit and waveform:
http://rocketresearch.nekrom.com/new/transformer chopper voltage%...
http://rocketresearch.nekrom.com/new/transformer chopper voltage%...
ltspice file:
http://rocketresearch.nekrom.com/new/transformer chopper voltage%...
cheers,
Jamie
Hi Jamie,
Vout is the DC output voltage to be sensed.
V2 is the drive to the AM chopper transistors
where you have V1 is actually the output of the circuit - it is
AC, at
the same freqency as V2, but the amplitude is Vout*R2/(R2+R3)
(roughly).
What Joerg & MooseFET are talking about is then using V2 to
synchronously demodulate this AC output - e.g. with a 4066, or
Joergs
suggestion which is even simpler.
Ok I hooked it up right now I think, I am not sure if the waveforms
are correct, it looks like it would be pretty hard to sample the
voltages as the peaks are very fast.
http://rocketresearch.nekrom.com/new/transformer chopper voltage%...
V(n001) the green trace is the output voltage of L4 on the R1 side,
and V(n003) is the voltage at the common node of R3 and R2 (the
divided voltage from 120VAC.
So do these traces look correct for doing the "demodulation"?
Also what
about FM would that work too, or is this AM method the way to go?
here's the corrected
circuit:http://rocketresearch.nekrom.com/new/transformer chopper voltage%...
ltspice
file:http://rocketresearch.nekrom.com/new/transformer chopper voltage%...
V2 should be a square wave.
The L4, L5, L6 transformer should end up with a near squarewave
on it
That is V2 times the voltage from V1
The L4, L5, L6 transformer may need a load resistance on the L4
section. A small capacitor may also be needed to kill the spikes.
Checked V2, it is a squarewave, gives similar results whether it is
AC or DC squarewave current.
Here are the L4, L5 and L6 waveforms:
http://rocketresearch.nekrom.com/new/transformer chopper voltage%......
The overall
circuit:http://rocketresearch.nekrom.com/new/transformer chopper voltage%...
I changed the V1 source to DC and got the same output spikes in
L4 as when it is AC.
Those currents look not too far from right. Carefully recheck stuff
including the dots on the inductors. Try dropping the K value of the
coupling to perhaps 0.25 to see that the inductors work right when
they are not coupled.
I checked the coupling, and changed the L5 and L6 coil winding (dots)
to have both dots on the centertap,
Both transformers should look like this:
0
))))))
==============
))))) ))))
0 0
Note where the dots are
hmm, the two primary coils are 180 degrees out of phase, with nice
looking waveforms but the secondary has just a few fA and pV on it
now!
cheers,
Jamie
operator error.
to think of it another way: its a very low power push-pull converter.
being very low power, you can feed the center-tap of the "primary" via a
voltage divider. if you get no secondary voltage, your sim is wrong.
to start with, throw away L1 - L3, and just drive ideal switches with a
complementary square wave. all L1-L3 does is allow the non-isolated
primary to provide the drive signals to the isolated voltage sampling
circuit (Qn, L4-L6). this is only necessary so you can then easily
synchronously rectify the output of L4.
personally, I like to use ideal components in my sims, to get the basic
concepts up and running. once you have proved the concept, *then* toss
in FETs/bipolars/leakage inductance etc. until you become an expert at
your particular sim package, this is a good approach.
Or just grab a few Mini-Circuits transformers and built it. A computer
may need 30 seconds to boot but my Weller heats up in 15 seconds