Your schematic is of a boost converter running open loop. The duty cycle of your generator connected to pin 3 of the LM311 will control the output voltage. When Q3 turns on, you have in essence placed a voltage step across and inductor. The current will start to linearly ramp up until the transistor turns off. During this, on time, D10 is back biased and all the energy being delivered to the load is coming from C10. When the transistor turns off, the flux collapses, the voltage across the inductor reverses, and the inductor current now starts to ramp down as you draw energy out of it. The output voltage in a boost converter is ALWAYS larger than its input voltage, so the output will be the input voltage plus the voltage across the inductor.
There are of course limits to the way you run this converter… you have to consider the switching frequency, the duty cycle and the saturation current of the inductor. For example… if the switching frequency is really low and the duty cycle is high, the inductor could saturate, at which point it stops being an inductor, and you can say bye-bye to Q3 because there is nothing to limit the current.