The second transformer will either saturate immediately or will not saturate. It is a magnetic, not a thermal phenomenon. It may overheat, also, depending upon loading and possible saturation.
Well designed transformers applied within their ratings are among the most efficient items of electrical equipment. Assuming they are well designed and are used within their ratings, you can probably assume something like 95% efficiency. That is, output power will be about 95% of input power. Of course, things get worse when you draw output current in surges, as with a capacitor-input filter with large capacitors, or when you draw large output currents because more power goes into heat due to (I^2)R losses in the copper windings and the resistance of the copper increases with increasing temperature.
What is your application, or are you just trying to understand transformer theory? By the way, yes, if you used one of your transformers to feed the second, and if there was no saturation of the second, and you were drawing no current, the output voltage would be 6 times the input voltage. Input/output current ratio would be the inverse of the input/output voltage ratio except that you have an additional "magnetizing current" at the input that is independent of the load current. This is the current you measure at the input of a transformer with no load on the secondary.
awright