transistors

[Kevin Weddle]

I wanted to know if someone could corroborate this point in theory. When a signal is applied to the emitter of a transistor, it is divided by re. When the signal is applied to the base, it divides in the other direction re. This makes re division bidirectional. Am I correct about this assumption?

 

[audioguru2]

Kevin,
If you feed a signal into the low resistance emitter of a transistor, the signal will be divided only if the signal's source resistance is too high.
The same thing applies to feeding a signal into the medium resistance (or high resistance if there is an emitter resistor) base of a transistor, the signal will be divided only if the signal's source resistance is too high.
Re is not bidirectional. Your voltage division occurs externally, due to the voltage drop across your too-high-in-value signal's source resistance.

 

[Kevin Weddle]

Re division is an inherent property of the transistor and the signal is divided by it. It has nothing to do with source resistance. Could somebody corroborate the bidirectional re?