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Hero999
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http://www.spycameracctv.com/spycamera/infra-red-day-night-wireless-outdoor-cctv-camera
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Thanks Hero999. Can you tell me where I can find these types of transformers?
It's not a standard part. Most transformers have mains voltage primary (typically 110V or 230V) not 24V.This transformer is used in a control card of a weaving machine. Also, is there a way to know which pins correspond to which secondary? I mean which secondary is rated to which current? All I know about this transformer is 1-2 is primary, 3-4 no pins, 5-6, 7-8, 9-10 are three secondary windings.
Yes, it should be easy to measure them with a multimeter: the secondary with the highest current rating should have the lowest DC resistance. -
Silly question.
Off course Microchip won't write your program for you (unless you pay them lots of course). It's something you've got to do yourself. -
I agree, it's confusing. The transformer appears to have four windings: a 24V primary and three 15V secondary windings, two rated to 15mA and one rated to 40mA.
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http://pdf.dzsc.com/QM2/QM20.pdf
What's the trigger voltage?
Post a schematic. -
What parts of the questions are you struggling with?
Have you attempted them yourself? -
The link doesn't work.
What do you want us to do about it? -
You can combine numerous electrolytic capacitors and achieve a very high current. The NE555 timer can be used or another IC or circuit.
No you can't achieve a very high current. Regardless of the capacitors used, the 555's maximum output current is 200mA, which limits the maximum current from the circuit to 100mA, at which point there will be a large voltage drop. -
You need a copy of the schematic or at least to reverse engineer the part of the circuit surrounding the resistor.
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Sorry, I don't know what you're talking about.
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You forgot to say what your question is.
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So, in this particular project, can I just install 6 or 12 (instead of all 24) LEDs?
Of course you can. Why would you think otherwise?Do I then use just 2 or 4 of the resistors? Where are they connected? And what then do the power requirements change to?
What do you think? -
Please post a schematic.
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Why do you need to switch it so fast?
Is 100ns the minimum on, off time or both? -
SPAM REMOVED BY MODERATOR
Transistor Zener Diode-MOSFET-IGBT-CAPACITANCE DIODE-IGBT-Frequency Diode Search--PIN-,SCHOTTKY Diode,SWITCHING Diode
Don't forget to thank me
What thank you for spamming the forum with some dodgy Chinese site probably selling fake components?
Cheeky sod. -
Without a part number or datasheet there's no way of knowing.
Generally infra red LEDs have a higher current rating than visible LEDs because their forward voltage is lower (1.1V to 2.5V, as opposed to 1.8V to 4.5V) and the maximum rated power dissipation is similar. -
Don't worry, it's normal for a power supply to have a slightly higher voltage when unloaded. If you connected the laptop and turn it on, you'll probably find the voltage drops to within 19V or so.
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No, it shouldn't be a problem.
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try a site called
radio-circuits.com
Why would anyone want to go there?
It's just a load of crappy circuits copied from other sites, nothing new nor innovative. -
I don't know which circuit will work best for you, try them both.
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It seems like an overly complicated way of doing this.
I think you should drop the MUX and three channel photodiode, use a single channel photodiode and turn the LEDs on, one at a time and take an intensity measurement for each colour. -
The same basic blocking oscillator circuit, normally used to drive a flyback transformer, can also drive a centre tapped or dual primary mains transformer.
Here's an example of a capacitor charger using a mains transformer with a centre tapped primary. It should be able to drive a voltage multiplier circuit.C1 1 uF D2 1N4948 R2 +------||------+ T1 1.2kV PRV 1K 1W | | +-----|>|-----/\/\---+------o + | R1 4.7K, 1W | red ||( blk | +-----/\/\-----+------+ ||( | | yel )||( +_|_ C2 + o----------------------------------+ ||( --- 300 uF | red )||( - | 450 V | +--------------+ ||( | | Q1 | ||( blk | 6 to 12 | |/ C +--------------------+------o - VDC, 2A +----| 2N3055 Stancor P-6134 D1 _|_ |\ E 117 V Primary (blk-blk) 1N4007 /_\ | 6.3 VCT Secondary (red-yel-red) | | - o------------+------+
http://www.repairfaq.org/sam/samschem.htm#schssi -
The amplifier has too higher output impedance to power a 4R speaker. You need a power amplifier. The circuit you've posted is for a signal amplifier.
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A voltage multiplier developes a DC voltage from the positive or negative cycle. The input is capacitvely coupled and the sinewave has this DC offset. A squarewave cannot be coupled with a capacitor, so the output is this DC offset when not in transition.
The piezo needs to be driven by a 100Hz square wave.
How can a voltage multiplier circuit (which will convert this to DC) possibly work?
If the signal generator had enough current capability (it doesn't) a simple step-up transformer would work but that's not an option here. An amplifier is required, which means a separate 100V supply voltage.
Help with voltage regulator
in Electronic Projects Design/Ideas
Posted
What's the minimum input voltage?
The LM317 will do. It'll need additional components to work up to 10A. A siwtching regulator is probably the best solution for you. Refer to page 19 of the datasheet. You'll need to uprate the components in the examples to get it to work up to 10A.
http://www.ee.buffalo.edu/courses/elab/LM117.pdf