Search results

  1. walid1

    Where the Archive ????

    It is a great loss
  2. walid1

    Where the Archive ????

    We have discussed several subjects did not find an old Please help
  3. walid1

    Pi filter for impedance matching

    Thank you KevinIV for reply my question is why and how filter amplify signals??
  4. walid1

    Pi filter for impedance matching

    Hellow, I build the following pi filter to match 100 ohm source to 1000 ohm load, I did the calculations based on RF Circuit Design Book As u can see at the center freq fc = 30MHz & Q=15 I had 3.771dB, I was surprised by where this value? this is amplification!!!! The second question is...
  5. walid1

    ::) Electronic magazine for you

    January 2007 http://rapidshare.com/files/9994391/Jan07.pdf
  6. walid1

    ::) Electronic magazine for you

    I am sorry, my dear Ante,the last issue I have is February 2007.
  7. walid1

    Negative resistance experiment

    Hi Ann I wish that the dialogue is always reply point by point. I spend a long time in the preparation of the question therefore hope that the reply on the points that I'm asking about them specifically and not a general answer. The question that I wish to find a definitive answer for is : Why...
  8. walid1

    ::) Electronic magazine for you

    Here is another one http://www8.rapidupload.com/d.php?file=dl&filepath=39423
  9. walid1

    ::) Electronic magazine for you

    If this is not forbidden, I have many of them and I can give you for the benefit
  10. walid1

    ::) Electronic magazine for you

    I submit this electronic magazine as a gift to the best forum in the world http://www8.rapidupload.com/d.php?file=dl&filepath=39239
  11. walid1

    Crystal examiner

    I do not have the necessary equipment, but I submit this link to enrich the subject http://www.giangrandi.ch/electronics/crystalfilters/xtaltest.html
  12. walid1

    Crystal examiner

    Hi TO audioguru: (a) Clear from your talk that you agree with AN920 that this is not good design. (b) I thought that it is banpass filter. i think it is 3rd order because it is 3 elements filter. Let me look at the internet for further information on this filter. TO AN920 I have long believed...
  13. walid1

    Automatic heat detector

    Thank you, I am very happy about your presence among us more than happy to answer, because I miss you and I intend to send a special message to you. I thank God that you are fine. Possibilities in Canada very large, but in Palestine almost nothing, we are therefore interested in those circuits...
  14. walid1

    Automatic heat detector

    Hi I found this circuit Saved in my PC (pdf formatt) and I do not know of any site obtained. This part is what concerns me now This part does not really care because I will focus on how to use transistor as heat detector. The writer wrote the following passage : My question: Is this talk...
  15. walid1

    Crystal examiner

    Hi An920 While I am looking into the Internet, I encountered the following firure from the Web site : http://www.k8iqy.com/qrprigs/2n215/2n215page.htm As you see in the picture C21 is less ten times than the upper C20, and this violates what we agreed upon in previous commentary. I think that...
  16. walid1

    Negative resistance experiment

    Hi AN920 I thank you for your wonderful to deliver some of the concepts that are new, at least for me. I want to know from a practicle perspective, I want to know the importance of this subject. Where we need to calculate the -ve resistance? I did some search and get the following...
  17. walid1

    Crystal examiner

    Hi AN920 What the meaning of: I am O+ who loves EE in a mainly <-O world.  thanks
  18. walid1

    Crystal examiner

    Hi AN920 Thanks to the rapid and excellent reaction. I have only a digital multimeter Equipped with the function of measuring capacitance. i have not an oscilloscope or function generator. Therefore, I will not be able to know the parameters of any crystal using the methode mentioned above. The...
  19. walid1

    Crystal examiner

    Hi AN920 I was very happy when I read your reply, I wish you a long and happy life, thank you very much. (1) (a) That is the same as: SQRT(RS* DC gain) = SQRT(50 * 100) = about 70 (correct me) (b) What this value? I mean what does that mean? (2) omega = 2 * pi * freq (yes it is) The rest is...
  20. walid1

    Crystal examiner

    Thank you AN920, (1) (a)It was difficult to obtain any information from the seller in my country. How can measure these parameters by network analyzer? (b) Do you not see that the value of Ls = 0.08H is very large value? (2) Can you shed more light on this point and the relationship between...
Top