30v DC to 27v DC

colum

Jul 25, 2013
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In order to drive an AC generator at the correct speed that uses a 27v DC motor for rotation...The 27v DC motor draws 6amps.
I have built a power supply that delivers 30v DC so I must lower this voltage 3v. I would appreciate any help on how I would do this without starting all over again.
The current set up is a simple 120v AC to Transformer to Rectifier to Motor..Thanks..colum
 

KrisBlueNZ

Sadly passed away in 2015
Nov 28, 2011
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You want to drop 30V DC down to 27V DC with a load of 6 amps?

A few diodes in series are a simple option.

Go to Digikey's parametric selection system: http://www.digikey.com/product-search/en/discrete-semiconductor-products/diodes-rectifiers-single

Check the "In stock" box. In the "Current - Average Rectified" column, select everything from 8A to, say, 20A (hold down Shift and use the arrow keys to select multiple lines). In the "Mounting Type" column, select the mounting types you want - you'll probably want to avoid surface-mounted devices. Click "Apply Filters".

Below the Apply Filters button, in the Quantity field, enter 1 and press Enter. This will move the devices with high minimum order quantities to the bottom of the table. Then sort the table on whatever parameter you're interested in - e.g. price, package, etc.

Look in the "Voltage - Forward (Vf) (Max) @ If" column to get an idea of the amount of voltage the diode will drop. The value in this column is a maximum value, not a typical value, so download the data sheet for any diode you're considering and look at the typical forward voltage vs. forward current graph. Voltages in series add together, so you'll need to choose a number of diodes that add up to about 3V.

Power dissipation in each diode is equal to the current through the diode (6A) multiplied by the voltage dropped across it. A few watts will make the diode pretty hot and they will probably need heatsinking. TO-220 packages are easier to heatsink than the cylindrical ones.

Other specifications aren't really important. High speed is irrelevant for this application but isn't a problem. Standard diodes have a voltage drop of about 1V; Schottky diodes have a significantly lower drop, but are sensitive to reverse voltages; I would connect a resistor (e.g. 10 ohms) across each one, if you use Schottky diodes, as protection.

If your load current is very constant, you could just use resistors instead of diodes. To drop 3V at 6A you need 0.5 ohms; this could be made from a number of higher-value resistors connected in parallel. Total power dissipation will be 18W.
 

eman12

Aug 24, 2013
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Hi,

Agreed with KrisBlueNZ.
For DC loads using diodes in series is one of the simplest methods.
 
Last edited:

duke37

Jan 9, 2011
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A DC motor will vary its speed with the loading. If you need an accurate frequency with varying load, then a voltage control will be necessary.

A slightly high voltage will give a slightly high frequency, this will be better than a low frequency.
 

colum

Jul 25, 2013
180
Joined
Jul 25, 2013
Messages
180
You want to drop 30V DC down to 27V DC with a load of 6 amps?

A few diodes in series are a simple option.

Go to Digikey's parametric selection system: http://www.digikey.com/product-search/en/discrete-semiconductor-products/diodes-rectifiers-single

Check the "In stock" box. In the "Current - Average Rectified" column, select everything from 8A to, say, 20A (hold down Shift and use the arrow keys to select multiple lines). In the "Mounting Type" column, select the mounting types you want - you'll probably want to avoid surface-mounted devices. Click "Apply Filters".

Below the Apply Filters button, in the Quantity field, enter 1 and press Enter. This will move the devices with high minimum order quantities to the bottom of the table. Then sort the table on whatever parameter you're interested in - e.g. price, package, etc.

Look in the "Voltage - Forward (Vf) (Max) @ If" column to get an idea of the amount of voltage the diode will drop. The value in this column is a maximum value, not a typical value, so download the data sheet for any diode you're considering and look at the typical forward voltage vs. forward current graph. Voltages in series add together, so you'll need to choose a number of diodes that add up to about 3V.

Power dissipation in each diode is equal to the current through the diode (6A) multiplied by the voltage dropped across it. A few watts will make the diode pretty hot and they will probably need heatsinking. TO-220 packages are easier to heatsink than the cylindrical ones.

Other specifications aren't really important. High speed is irrelevant for this application but isn't a problem. Standard diodes have a voltage drop of about 1V; Schottky diodes have a significantly lower drop, but are sensitive to reverse voltages; I would connect a resistor (e.g. 10 ohms) across each one, if you use Schottky diodes, as protection.

If your load current is very constant, you could just use resistors instead of diodes. To drop 3V at 6A you need 0.5 ohms; this could be made from a number of higher-value resistors connected in parallel. Total power dissipation will be 18W.

Thanks Kris for your advice I will contact Digikey as you suggested and I must find a circuit to use Zeners as I thought the would be in paralell .. Be well and thanks ..colum
 

colum

Jul 25, 2013
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Hi Kris I'm new at this and my response (quote) ended up in an unexpected place anyway thanks for your valuable advice...colum
 
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