BJT power supply

Kevin Weddle

Feb 23, 2004
1,620
Joined
Feb 23, 2004
Messages
1,620
The regulator does not have output filtering as switching regulators must have. Is the 555 really prepared to deliver a linear result under a massive voltage swing and load on the 555 that could be anything given the the surrounding circuitry. Don't like switching regulators to begin with and I can't determine any feedback if even they use it. What is that zener doing? A constant gate voltage?

 
Last edited by a moderator:
A

Alun

Jan 1, 1970
0
index.php


Kevin, this is not a switching regulator it's a linear regulator just like the LM7805.

The switching element just doubles the supply voltage to lift the gate of the MOSFET high enough above the output in order to turn it fully on.

The zener is not a normal zener diode, it's a programable shunt voltage regulator, it adjusts the voltage on the gate of the MOSFET to keep the output voltage constant.
 
Last edited:

ante1

Jan 24, 2004
4,138
Joined
Jan 24, 2004
Messages
4,138
Hi Kevin,

I think maybe you might have to read up on the subject! ;D

 

ante1

Jan 24, 2004
4,138
Joined
Jan 24, 2004
Messages
4,138
Hi Alun,

It might work but for stability don’t you think there need to be some kind of voltage stabilizer for the op-amp more than just the 10uF cap? The op-amp is more likely to be sensitive to fluctuations in the voltage than the original TL 431, they work in a completely different way.
Just a thought! ;D

 

audioguru2

Apr 6, 2004
12,026
Joined
Apr 6, 2004
Messages
12,026
Hi Guys,
If Alun uses a P-channel Mosfet in his circuit then he won't need a 555 voltage doubler. ;D
The MC33171 is a low-power fairly slow opamp. I would use a faster one.

 
A

Alun

Jan 1, 1970
0
Sorry, I misread you last post, I'm the one who needs my eyes testing. ;D

I already knew I could've used a P-channel MOSFET, but they have a larger on resistance.

I was wrong earlier when I said I don't need a fast op-amp, I do because the MOSFET is connected as a source follower so I wouldn't getr any voltage amplification, but I would if I used the P-channel idea which would have a better transient response.

By the way couldn't you think of a cheap, faster, low power op-amp with a low saturation voltage? ;D

 

audioguru2

Apr 6, 2004
12,026
Joined
Apr 6, 2004
Messages
12,026
Hi Alun,
This is a linear regulator so the on resistance of its Mosfet doesn't matter unless it is drawing about 40A or more, but then the poor thingy would melt anyway.
I selected the MC34071 because it is the same as the MC33171 that you used except it is faster (10V/us), saturates with a lower loss and can output higher current. At Digikey it is cheaper than yours. Isn't it nice that the dual version of both ICs costs exactly the same as a single one of yours.
Looky, looky again. ;D

 
A

Alun

Jan 1, 1970
0
audioguru said:
Hi Alun,
This is a linear regulator so the on resistance of its Mosfet doesn't matter unless it is drawing about 40A or more, but then the poor thingy would melt anyway.
Yes I know, but a lower on resistance means a lower dropout voltage.
 
Last edited:

ante1

Jan 24, 2004
4,138
Joined
Jan 24, 2004
Messages
4,138
Hi Guys,

Looks good, and what would you use as Vref?

 
A

Alun

Jan 1, 1970
0
Any low current constant voltage source such as a shunt referance made with a zener diode and resistor,  or a voltage referance IC such as a a band gap referance.

 

ante1

Jan 24, 2004
4,138
Joined
Jan 24, 2004
Messages
4,138
Hi Alun,

So, why did you omit the TL 431 then?

 
A

Alun

Jan 1, 1970
0
To make people think. ;D

No seriously, often things like voltage referances and current sources aren't shown because they can be any of many things. Here it could've been a zener diode and pullup, band gap reference such as the LM113 or the programable shunt regulator TL431A. The person using this circuit can decide and choose which type of volatge referance is best for thier application.

 
Last edited:

ante1

Jan 24, 2004
4,138
Joined
Jan 24, 2004
Messages
4,138
Hi Alun,

Well you did it, made me think that is! I had to since you went from a complete circuit to an improved one and left some blanks in there! ;D
I know what you mean. 8)

 
Top