Hello,
Do you want to create a sine wave?
Then have a look at SPWM (sine wave pulse width modulation).
www.homemade-circuits.com
You can use the signals on pin 8 and 9 to drive your H-bridge.
Bertus
Do you want to create a sine wave?
Then have a look at SPWM (sine wave pulse width modulation).
Arduino SPWM Generator Circuit - Code Details and Diagram - Homemade Circuit Projects
In this post we learn how to generate sine wave pulse-width-modulation or SPWM through Arduino, which can be used for making a pure sine wave inverter circuit or similar gadgets. […]
www.homemade-circuits.com
Bertus
Delta Prime
- Jul 29, 2020
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Dead times are necessary to mitigate any risk of current shoot through between the switching power FETs. Integrated FET drivers often have a feedback based self timed FET switching sequence to ensure the smallest possible dead times while avoiding any shoot through current.
Which brings up another question?
What is shoot through current?
that no two IGBT in your inverter or for that matter your H-bridge in the same limb (power buss),turns ON at the same time. An ideal power electronic switch during ON state behaves like a conductor and thus if two switches in the same limb turn ON simultaneously, they will cause the DC bus to short-circuit, This is called a shoot-through fault. because I am an Electronic Technician I have troubleshooted various advanced microcontroller used for gate-driving, there are various causes which may lead to shoot-through fault to appear thus rupturing the costly switches. Few reasons are Electromagnetic Interference due to HF (high-frequency) operation, faulty snubber circuit design etc.
Class dismissed...
There will be a quiz tomorrow be ready for it...
I'll try both the square wave and the sinosoidal wave see which is better its just a matter of reuploading code but I do want at least 2 micro-seconds dead time though, I was under the impression that square wave would be more efficient becuase the practically keeping it's "on" for a longer period where a sinosoidal cuts the corners to make them smooth!
Last edited:
so another question is this 50 or 60Hz
C:
/*
This code was based on Swagatam SPWM code with changes made to remove errors. Use this code as you would use any other Swagatam’s works.
Atton Risk 2017
*/
const int sPWMArray[] = {500,500,750,500,1250,500,2000,500,1250,500,750,500,500}; // This is the array with the SPWM values change them at will
const int sPWMArrayValues = 13; // You need this since C doesn’t give you the length of an Array
// The pins
const int sPWMpin1 = 10;
const int sPWMpin2 = 9;
// The pin switches
bool sPWMpin1Status = true;
bool sPWMpin2Status = true;
void setup()
{
pinMode(sPWMpin1, OUTPUT);
pinMode(sPWMpin2, OUTPUT);
}
void loop()
{
// Loop for pin 1
for(int i(0); i != sPWMArrayValues; i++)
{
if(sPWMpin1Status)
{
digitalWrite(sPWMpin1, HIGH);
delayMicroseconds(sPWMArray[i]);
sPWMpin1Status = false;
}
else
{
digitalWrite(sPWMpin1, LOW);
delayMicroseconds(sPWMArray[i]);
sPWMpin1Status = true;
}
}
// Loop for pin 2
for(int i(0); i != sPWMArrayValues; i++)
{
if(sPWMpin2Status)
{
digitalWrite(sPWMpin2, HIGH);
delayMicroseconds(sPWMArray[i]);
sPWMpin2Status = false;
}
else
{
digitalWrite(sPWMpin2, LOW);
delayMicroseconds(sPWMArray[i]);
sPWMpin2Status = true;
}
}
}what kind of quiz!?Dead times are necessary to mitigate any risk of current shoot through between the switching power FETs. Integrated FET drivers often have a feedback based self timed FET switching sequence to ensure the smallest possible dead times while avoiding any shoot through current.
Which brings up another question?
What is shoot through current?
that no two IGBT in your inverter or for that matter your H-bridge in the same limb (power buss),turns ON at the same time. An ideal power electronic switch during ON state behaves like a conductor and thus if two switches in the same limb turn ON simultaneously, they will cause the DC bus to short-circuit, This is called a shoot-through fault. because I am an Electronic Technician I have troubleshooted various advanced microcontroller used for gate-driving, there are various causes which may lead to shoot-through fault to appear thus rupturing the costly switches. Few reasons are Electromagnetic Interference due to HF (high-frequency) operation, faulty snubber circuit design etc.
Class dismissed...
There will be a quiz tomorrow be ready for it...
ok cool thanks again!
Delta Prime
- Jul 29, 2020
- 2,987
- Joined
- Jul 29, 2020
- Messages
- 2,987
Apologies mosfets not igbt.
No quiz. I was Just kidding.
You doing a great job you're almost there.
thanks dood
I have a feeling that when I connect the transformer the potential difference that build up in the caps will collapse and come to a resting voltage but I have a plan
measure the output of the transformer divide it by the transformer ratio
get that digit and divide 240 by that number that will give me a new ratio
buy the corrosponding transformer with that ratio and just hope that there is enough current for my needs!
measure the output of the transformer divide it by the transformer ratio
get that digit and divide 240 by that number that will give me a new ratio
buy the corrosponding transformer with that ratio and just hope that there is enough current for my needs!
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