How this ps unit works??

walid1

Jun 27, 2004
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The circuit in the following figure (from: http://www.hobby-circuits.com/circuits/power-supply/dc-power-supply/891/variable-dc-power-supply) represents a variable power supply
Transistor Q1 is npn type
jb13441983361.gif

This was corrected in the following figure
jb13441983372.jpg

I have thought carefully about this circuit, but I could not get to the mechanism of how it work!
I think that when the transistor Q1 operates, it must turn off Q2.
I try to simulate it using multisim10, but it didn't work, that is when I change the value of any of P1 or P2 the output is fixed at near the retectified voltage.
Any help in clarifying the way this circuit work would be welcome, thanks

 

indulis

Nov 21, 2005
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Think about it this way... first remove the current limit stuff (Q3, R4, P1). Then what to do with Q1... the collector-base looks like a diode... that "kinda works". I don't see how making Q1 a n-p-n will work at all. Then add the current limit function back in.

 

Kevin Weddle

Feb 23, 2004
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A center tapped transformer is perfect for producing a negative dc supply voltage. This one doesn't have one.

 

Hero999

Oct 28, 2007
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KevinIV said:
A center tapped transformer is perfect for producing a negative dc supply voltage. This one doesn't have one.
This circuit uses a bi-phase rectifier. Each diode acts as a single phase rectifier but the AC voltage applied to D2 is 180o out of phase, thus full wave rectification is achieved.
 

Kevin Weddle

Feb 23, 2004
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Hello Walid, the circuit you found was I think novice. Q3 is an NPN. Indulis recommends removing the resistors and I agree. The load has to be high impedance. Most versatile regulators need to sink current sometimes.

 
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