LM338 Power Suply Current Regulator

Fight

May 26, 2010
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In lm338 data sheet asking
Features:
Guaranteed 7A peak output current
Guaranteed 5A output current

But problem is that in Electrical Characteristics:
Vin-Vout = 30V Than max current 1A
what is meaning that
lets Vin = 38V  and Vout = 8V
38-8 = 30



and Vin-Vout = 10V or less than 5A can handle
mean
38-28 = 10
mean 8 to 28V 1A handle
and 28 to above 5A handle

Attatch Diagram



2.    in Application Hints diagram all diagram is designed that can handle 5A

Attatch Diagram

View attachment 41018

View attachment 41019

 

hotwaterwizard2

Jan 8, 2004
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Exactly what are you wanting to do here?

You Must Heatsink the components for 5 amps each if not they will only handle 1 amp each.
There is another way to make a high current power supply.

View attachment 41022

 
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hotwaterwizard2

Jan 8, 2004
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http://www.national.com/ds/LM/LM138.pdf

http://www.national.com/mpf/LM/LM338.html#Overview

 

Hero999

Oct 28, 2007
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hotwaterwizard said:
Exactly what are you wanting to do here?

You Must Heatsink the components for 5 amps each if not they will only handle 1 amp each.
There is another way to make a high current power supply.
That circuit will have very poor regulation because the base-emitter saturation voltage of the 2N3055 will vary depending on the current drawn and the 0.47R resistors will have a significant voltage accross them.

Suppose the current draw is 0A and you set the voltage to 12V.

Then you increase the current to 5A.

@0A the VBE of the transistors will be near 0.6V.

Each transistor will have 5/6 = 833mA through it, the same for the emitter resistor.

The voltage will drop by the 0.47R resistor will be 5/6 View attachment 41026

View attachment 41027

View attachment 41028

 
Last edited by a moderator:

Hero999

Oct 28, 2007
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They help to ensure the current is shared equally between the transistors. The value isn't critical, I chose 0.1R because I originally designed it for high currents, for 5A you can use 1R which will be easier to get hold of.

 

Fight

May 26, 2010
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if i change the value of 1R instead of 0.1R than what change in circuit current
the resistor wattage
the voltage across R = ?
the current across R = ?

 

Hero999

Oct 28, 2007
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Changing the value will not change the current, the circuit does not provide current regulation, it's just that if the voltage drop across the resistors is very low, the current sharing won't be very good.

 

Fight

May 26, 2010
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it's just that if the voltage drop across the resistors is very low, the current sharing won't be very good.
please explain it using examples
if 10R resistor use than
 

Fight

May 26, 2010
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what is the efficiency of these circuit
if this method using with lm317 and lm338 than thses ic better current and voltage or not

 

Hero999

Oct 28, 2007
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please explain it using examples
if 10R resistor use than
There's no hard and fast rule, I just use current balancing resistors which have a voltage drop of a couple of hundred mV or so at full current. The voltage drop can be calaculated using Ohm's law.

what is the efficiency of these circuit
It's as efficient as an linear regulator.

if this method using with lm317 and lm338 than thses ic better current and voltage or not
?
 

Fight

May 26, 2010
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There's no hard and fast rule, I just use current balancing resistors which have a voltage drop of a couple of hundred mV or so at full current. The voltage drop can be calaculated using Ohm's law.
ok

Quote
if this method using with lm317 and lm338 than thses ic better current and voltage or not
?
my mean that if using transistor current increasing method for lm317 or lm338 regulator ic than this method ok or not because volatge vary from 1.2 to 30 v

7805 or 7812 is fixed regulator
 

Hero999

Oct 28, 2007
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The variable voltage requirement doesn't make any difference, why would it?

 

Fight

May 26, 2010
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Attatch diagram
first circuit is use for current limiting
transiter is use for current increasing transistor current provide 5A at all voltage range 1.2-30V
this circuit is good
better
best
or not

View attachment 41048

 

Hero999

Oct 28, 2007
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It's not a very good idea because the extra regulator will increase the drop out voltage by 4.2V.

 
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