Resqueline
- Jul 31, 2009
- 2,848
- Joined
- Jul 31, 2009
- Messages
- 2,848
The first schematic on page 18 now makes sense to me, but I am completely dumb founded how to mathematically analyse the circuit, since my knowledge of opamps is very limited. But I do get the jist of it, the op-amp changes the voltage applied to the ADJ. It is essentially running in differential mode, and will adjust it's output to try and equalize the two inputs I believe? How close am I?
Spot on in fact.
Let's call +Vout "common". The op-amp non-inverting input is connected to this.
R3 is the sense resistor and drops 1V at 5A.
The op-amp inverting input is connected to the positive side of R3 via R2, and to "minus 1.24V" via R5.
As the op-amp inverting input is pulled above "common" (by a rising voltage across R3) the op-amp output will swing negative and pull ADJ down via the diodes (LED lights).
At the 5A limiting point there's 1.24V across R5 (= 3.757uA) and R2 has to be set at 1V / 3.757uA = 266k Ohms. At 1A limiting it has to be at 0.2V / 3.757uA = 53k Ohms.
The circuit is not ideal, since the (somewhat significant) current that the LM contributes with is not measured by R3.
But Dave has some very sensible points. If you don't feel the need for having an adjustable current limit etc. now then just make the simple version (and fuse the mains input).
There's no point in biting over more than you can chew (at the moment). Making an ideal lab supply is also better/easier done without using these simple 3-terminal regulators.