jesteban Posted February 25, 2005 Report Share Posted February 25, 2005 Good Morning,I have a problem that maybe you can Help me with. I need a circuit that can satisfy the table below. Taking into account that RL = 1 Mohm and that opto-isolators are usedI attach a preliminary sketch I did, but I don't know if this will work or the values of the resistors that will make it workAny help will be greately appreciated. If you make any comments on the attachment itself you can send to directly to me at: [email protected]Thanks,Driving Voltages D0 D1 D2 D3 D4Stage1 0 0 1 0 1Stage2 0 1 1 0 1Stage3 1 0 1 1 1Stage4 1 1 1 1 1Stage5 0 0 1 0 0Stage6 0 0 0 0 0Jose BetancesOpto.pdf Quote Link to comment Share on other sites More sharing options...
audioguru Posted February 25, 2005 Report Share Posted February 25, 2005 Hi Jose,Welcome to our forum.Are you trying to make your own D to A converter? Quote Link to comment Share on other sites More sharing options...
jesteban Posted March 1, 2005 Author Report Share Posted March 1, 2005 Yes! I have to do a test for a Train inverter and designing this DAC circuit will help me a lot. Thank you! Quote Link to comment Share on other sites More sharing options...
jesteban Posted March 3, 2005 Author Report Share Posted March 3, 2005 Please!!!! I really need some help with this. Can anyone help me? Quote Link to comment Share on other sites More sharing options...
audioguru Posted March 3, 2005 Report Share Posted March 3, 2005 Google has 27,100 articles about "digital to analog converter" and this is just one of them:http://www.play-hookey.com/analog/d2a_converter.html Quote Link to comment Share on other sites More sharing options...
MP Posted March 4, 2005 Report Share Posted March 4, 2005 Jesteban,For a digital to analog converter, you are converting a binary number to analog. For example, binary #s in a 5 bit word are 16, 8, 4, 2, 1. 16 is Most Significant bit (MSB) and 1 is Least Significant Bit (LSB) in your 5 bit binary word. Therefore, you will use resistor values MSB = R, LSB = 16R to make the output voltage correct when it is summed. This sounds backwards, but you want the LSB voltage to be the smaller one coming out of the DAC.If this does not clear it up for you, then there is a pretty good explanation here: http://www.ibiblio.org/obp/electricCircuits/Digital/DIGI_13.htmlFor your example, look down the page 6 or 7 diagrams.Hope it is helpful.MP Quote Link to comment Share on other sites More sharing options...
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