Electronics-Lab.com Community

# Attenuation

## Recommended Posts

Hi, I am very confused about this subject of attenuation. I have a circuit posted, and it is working at a center frequency of 25Mhz. And I need to calculate the attenuation at 2nd, 3rd, 4th and 5th harmonics of 25Mhz. From internet I found this formula:
A(db) = -10 log(1+((w/wc)^2n)) where w is the desired freq. and wc is the center frequency, n is the number of elements (inductors and capacitors) in the circuit.

##### Share on other sites

• 2 weeks later...

This formula is wrong
it will not vork with your circuit
it means when you double frecuency it passes 4 time less voltage
for example its module of transfer function is
~1 at 25MHz
0.25 at 50Mhz
1/16 at 100Mhz
in your formula you must substitute 2 for n to get the correct result

##### Share on other sites

Hi sergen,

I have changed your image to a more suitable format for posting (PNG).
The size is now 10k instead of 2019.4k (200 times smaller) and it is easier to see to.
Please use this format, the pages loads much faster and members using dialup will be more comfortable.

## Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

×   Pasted as rich text.   Paste as plain text instead

Only 75 emoji are allowed.

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.