desoky675 Posted September 30, 2011 Report Share Posted September 30, 2011 It's about inverter circuit from this site http://powersupplycircuit.blogspot.com/2009/03/watt-power.htmlI've made it, but It didn't work, so i bypassed the first transistor "2SC1061" , It worked but at the other end of the transformer , It gave around 130v instead of 220V .So any one have an Idea, how to solve this problem. Quote Link to comment Share on other sites More sharing options...
Hero999 Posted September 30, 2011 Report Share Posted September 30, 2011 Please post a decent sized schematic.What do you mean by bypassed?If you remove one of the driver transistors the meter will only show half the voltage because the transformer is only being driven from half the voltage. Quote Link to comment Share on other sites More sharing options...
desoky675 Posted September 30, 2011 Author Report Share Posted September 30, 2011 This is a better image http://www.mediafire.com/imageview.php?quickkey=kpwqzq9kb9q8zq8&thumb=4I mean by bypass that I have removed the two "2cs1061" transistors and connected the output from the two amplifiers directly to the transistors "2N3055"I removed both of the transistors, because when they where in the circuit It didn't work, So please help.MODERATOR EDIT:Attached file.In future please use the forum attachment feature rather than file hosting services. Quote Link to comment Share on other sites More sharing options...
Hero999 Posted September 30, 2011 Report Share Posted September 30, 2011 There are plenty of things wrong with that circuit.Your best bet is to buy an off the shelf inverter.Send to that, you should remove the LM324 and replace the old BJTs with MOSFETs such as the IRL540. Quote Link to comment Share on other sites More sharing options...
audioguru Posted September 30, 2011 Report Share Posted September 30, 2011 The 2SC1061 transistors are driver transistors for the 2N3055 transistors. They amplify The 20mA from the output of the opamps to about 200mA. The maximum power output from the inverter will be very low without them. Maybe you had their pins connected backwards.Thje "corrected" circuit is completely wrong:1) The timing capacitor and resistor for the CD4047 IC have wrong values. See Texas Instruments datasheet.2) A zener diode is missing that protects the IC from voltage spikes.3) There are not enough output transistors for 500W.4) Two LM324 quad opamps are used instead of a single LM358 dual opamp.Here is a schematic that works: Quote Link to comment Share on other sites More sharing options...
Hero999 Posted September 30, 2011 Report Share Posted September 30, 2011 Using a Darlington triple is a poor way to increase the current gain because it has a voltage loss of 3V or more at high currents. I'll post a correction tomorrow. Quote Link to comment Share on other sites More sharing options...
Hero999 Posted October 1, 2011 Report Share Posted October 1, 2011 Wow, I've just looked at the datasheets for the transistors used and they're horrible! Their HFEs are low and saturation voltages high.I'd recommend using the circuit attached instead.The MOSFETs can be the IRF540N.Sorry the schematic is a little fuzzy, I can re-draw it more neatly, if you like.Here's a link to a much more complicated pure sine wave inverter.http://m.wpi.edu/Pubs/E-project/Available/E-project-042507-092653/unrestricted/MQP_D_1_2.pdf Quote Link to comment Share on other sites More sharing options...
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