What is the power dissipated by R2, R4, and R6?

charmcaster.engg

Mar 20, 2014
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What is the power dissipated by R2, R4, and R6?

mcq5_1010_1.gif
 

Arouse1973

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Well then that would be easy. I think he needs more help than that:)
 

Gryd3

Jun 25, 2014
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Well then that would be easy. I think he needs more help than that:)
Quote possibly, but he has demonstrated that he can calculate the equivalent resistance of a resistor network, as well as calculate power, current, and voltage drop.

It will take a little work to break down the drawing, but his demonstrated skills in the other posts should easily give him the answer.
I'd like to see what kind of effort has gone in so far. I've seen a lot of questions pop up recently.
 

davenn

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OK this looks like a homework style post, so I have moved it to homework

please answer appropriately :)

It will take a little work to break down the drawing, but his demonstrated skills in the other posts should easily give him the answer.
I'd like to see what kind of effort has gone in so far. I've seen a lot of questions pop up recently.

yup agreed :)

Dave
 

Laplace

Apr 4, 2010
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To calculate the currents using KVL,KCL.
That method will certainly give a correct answer. However, what is commonly done in this type of situation is to iteratively combine parallel resistances to ultimately find the total source current, then iteratively use current division to find the current in each branch. But if you have a symbolic algebra engine, then just write the node equations and let the computer solve it.
 

charmcaster.engg

Mar 20, 2014
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That method will certainly give a correct answer. However, what is commonly done in this type of situation is to iteratively combine parallel resistances to ultimately find the total source current, then iteratively use current division to find the current in each branch. But if you have a symbolic algebra engine, then just write the node equations and let the computer solve it.
Can you explain in detail how to perform iterative current division?I got total resistance as 6.26K n thus total current as 17.73mA.
 

Harald Kapp

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I got total resistance as 6.26K n thus total current as 17.73mA
This is correct. This is the current flowing through R1. From that you can calculate the voltage drop across R1 to get the voltage across R2. From the voltage across R2 you can calculate the current through R2 and thus the power dissipated by R2.

Apply Kirchhoff's laws to get the current through R3 (you know currents through R1 and R2 by now). Move forward repeating the same calculations as above for the other resistors (calculate voltage drops, calculate currents etc.)
 

charmcaster.engg

Mar 20, 2014
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This is correct. This is the current flowing through R1. From that you can calculate the voltage drop across R1 to get the voltage across R2. From the voltage across R2 you can calculate the current through R2 and thus the power dissipated by R2.

Apply Kirchhoff's laws to get the current through R3 (you know currents through R1 and R2 by now). Move forward repeating the same calculations as above for the other resistors (calculate voltage drops, calculate currents etc.)
Thanks!
 
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