help with IR2110 chips

Delta Prime

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Single-phase transformers
kVA = (load voltage x load current)/(1000 x load power factor)

[Mod edit: corrected wrongly inserted link]
 
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Maglatron

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Single-phase transformers
kVA = (load voltage x load current)/(1000 x load phttps://eepower.com/technical-articles/how-to-design-a-transformer-size-and-selection/ower factor)
bookmarked!
 

Maglatron

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cool did you get what I meant when I said that the that the potential in the capacitors would collapse a moment after attaching the transformer to the circuit? because apart from the primary coil's resistance it's basically a short! what are your thoughts on this please?
 
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Maglatron

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cool did you get what I meant when I said that the that the potential in the capacitors would collapse a moment after attaching the transformer to the circuit? because apart from the primary coil's resistance it's basically a short! what are your thoughts on this please?
does anybody out there know what I'm talking about?
 

Maglatron

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funny you should say that I've just been trying to mess about with spice, I don't know how to model my machine, so first step, going to take measurments of the coils raw ac put them through the rectifier (in spice) and set the frequency and put in the capacitor bank, so that's the plan for the minute, and make the spice simulation as close to the the real thing as possible, thanks though! what I do know is that the magnets pass the coils on one side of the wheel and the magnets on the other side of the wheel are 1/3rd out of phase and need to be able to model this the white circles represent the coils!
 

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Delta Prime

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cool did you get what I meant when I said that the that the potential in the capacitors would collapse a moment after attaching the transformer to the circuit? because apart from the primary coil's resistance it's basically a short!
I'm talking generalities here.
The primary windings of a AC transformer are insulated aluminum or copper and are wound around a central core that is hooked up to utility or mains power popular frequencies are 50 hertz 60 HZ 400 Hz because of this alternating frequency the transformer primaries present an inductive reactance
Which resists the flow of current. No Short circuit because of the magnetic flux within the core of the transformer.
But on secondary side full wave bridge rectifier with filter capacitors. The charging process of the capacitors present themselves as a short to the rectifiers; an in- rush of current could potentially destroy the diodes.
A series connected positive temperature coefficient thermistor along with your choice of a thyristor and or relay will mitigate that potential for overcurrent and or in-rush current.
 

Maglatron

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I am not talking about stepping down mains to then rectify with filter caps but thank you for trying I'm talking about rectifying the AC voltages from the coils on my machine putting a smoothing cap, inverting that DC voltage (which is 55VDC) to 55VAC and using a transformer to step up the voltage with a ratio of 1:4.2 for approximatly 230VAC
 

bertus

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Hello,

When the Vpeak is about 55 Volts, the effective voltage will be about 39 VAC.
The 230 VAC is an effective voltage. The peak voltage will be about 320 Vpeak.
There is a factor of square root 2 between VAC and Vpeak.


Bertus
 

Maglatron

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I dont get it if I'm using 55vdc and inverting it then the out put should be 55vac multiplying by the transformer ratio 1:4.2 gives 230vac
 

Maglatron

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also I just remembered that the reason I'm using sqaure wave input is because it cuts out rms
 

bertus

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Hello,

55 VDC will generate a sinus of about 39 VAC.
You need to apply the 0.707 factor to find the effective AC voltage.

Bertus
 
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