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  1. Electric1

    Calculation of Gate Resistance

    I tried to follow the below article from Infineon for gate resistance calculation GateResistance for method1 based on the switching time, my doubt is for the gate driver in case 2 Mosfets are connected instead of 1 Mosfet will gate resistance will increase or decrease and by what factor will it...
  2. Electric1

    Oscilloscope samples/sec and memory depth parameter

    I have few doubts Here before T there are negative values of time (-3us, -2us, -1us, 0, 1us, 2us etc) what does it indicate? After i changed the T position by moving the position button the time becomes positive what does this indicate? which one should i set? Also The number of points...
  3. Electric1

    Oscilloscope samples/sec and memory depth parameter

    Yes i mean a hall effect sensor, thank you for clear explanation.
  4. Electric1

    Oscilloscope samples/sec and memory depth parameter

    RIGOL DHO924
  5. Electric1

    Oscilloscope samples/sec and memory depth parameter

    Please confirm me on the oscilloscope settings is correct or not, suppose the maximum frequency of the hall signal is 300 Hz which correspond to 1/300Hz = 3ms. As the frequency of the signal is less if i keep the oscilloscope settings to 100K samples/sec which according to me 1/100,000 = 10uS...
  6. Electric1

    RMS and Average Value Difference

    Vavg = \frac{\int_0^\pi V\sin(wt) w dt}{\pi} = V*2/\pi =V* 0.637 Only positive cycle is considered above, it is confusing each book is following different methodologies.
  7. Electric1

    RMS and Average Value Difference

    The average value of the above waveform should be 0 as it has equal areas on the positive and negative side. What am i missing here?
  8. Electric1

    RMS and Average Value Difference

    But as you can see in post2 the power calculations are not matching, why?
  9. Electric1

    RMS and Average Value Difference

    The power is calcualted as time average of V * I 1/0.1*(10*4*0.02) = 8Watts. ->1 Power using average voltage and current 7V * 2A = 14Watts ->2 Power using the RMS voltage and current 8.3V * 2.82A = 23.4 Watts. ->3 So both 2 and 3 do not match 1, probably i cannot use 2 and 3 for power...
  10. Electric1

    RMS and Average Value Difference

    For the above waveform i can calculate the Average value and the RMS value as below Avg Voltage = 1/0.1*(10*0.07 + 0 * 0.03)=0.7/0.1 = 7 V Avg Current = 1/0.1*(0*0.05 + 4 * 0.05) = 2 A Rms Voltage = 10*Sqrt(D) = 10*Sqrt(0.7) = 8.3V RMS Current = 4*Sqrt(0.5) = 2.82A Now my main question is...
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