conntaxman
- Jun 17, 2011
- 89
- Joined
- Jun 17, 2011
- Messages
- 89
Im just learning so bare with me. I want to use leds for a small light. I know that the supply voltage is very low and you will Burn out the led it you go above that. Now im confused a little with the LM317. Link http://www.reuk.co.uk/LM317-Current-Calculator.htm
they are saying that all you need is that one resistor to light the led with about 20ma. So now if the input voltage is 12vdc wouldn't that come out as about 9 volts seeing that the 317 looses about 3 vdc. I have two small batteries 3.2vdc x 1000ma. and Im going to make a solar charger also useing the LM317 . I will be putting the 2 batteries in seires ,6.4 volts..
I know that the first question said that I was going to feed the leds with 12vdc.
I just want to know about the voltage and the amp. part for the OUTPUT pin. I thought it would have to be about 2 volts x 20ma for the led
tks
John
I know dumb question. but if you don't know the answer it isn't.
they are saying that all you need is that one resistor to light the led with about 20ma. So now if the input voltage is 12vdc wouldn't that come out as about 9 volts seeing that the 317 looses about 3 vdc. I have two small batteries 3.2vdc x 1000ma. and Im going to make a solar charger also useing the LM317 . I will be putting the 2 batteries in seires ,6.4 volts..
I know that the first question said that I was going to feed the leds with 12vdc.
I just want to know about the voltage and the amp. part for the OUTPUT pin. I thought it would have to be about 2 volts x 20ma for the led
tks
John
I know dumb question. but if you don't know the answer it isn't.