Kevin Weddle
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Everything posted by Kevin Weddle
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I think at 1Khz, the capacitor could not completely charge in one cycle. No, that's not it. You have to make the resistance higher than the impedance of the capacitor.
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Something I noticed about voltage multipliers. I've never seen two equally charged capacitors reverse bias a diode. But as long as the capacitors are completely charged the diode is reverse biased.
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I know there is a simpler 15V to 45V voltage multiplier than the one I posted. It might be adequate. I won't bother posting that one.
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Wow this Windows 10 is great.
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Thanks guys. I love to hear you.
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They always conduct. No matter what. These two circuits are different. Resistors don't clamp a voltage. The voltages halve, halve, and halve again until Vp. ac.pdf
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The other equation is Xc - Xl. So a series LRC is only inductive or capacitive.
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In the quation v = L di/dt. The voltage goes up and the current goes up. In the equation i = C dv/dt. The voltage goes up and the current goes up.
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The only addition I'll add to my post is the current of the capacitor must at least be C dv/dt.
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Capacitor's pull current through a resistance. Then you have voltage momentarily.
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I went ahead and built this circuit today. The input resistor voltage changed very little. The output transistor voltages changed quite a bit.
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The schematic shown has a gain of 10. I changed the gain to 10,000 in this circuit. I don't know how unstable that would make it. I guess I'll have to match the opamp and output transistors.
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computer power supply
Kevin Weddle replied to Kevin Weddle's topic in Electronic Projects Design/Ideas
The serialcom is a standard USB. So I guess it doesn't matter. It may be different from the more common computer power supply. -
I've got a computer with an external DC power supply. Does this affect the serialcom connection?
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Here is a good 3A 0v-30v power supply.
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This could be a better circuit.
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Yes, maybe the transistors should be in the negative feedback loop of the opamp. But this circuit has to have similar function over much of the operating range. I know the impedance of 200k looks higher than the transistor impedance. But the voltage is relatively the same.
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No Hero99, that gain of 10 circuit is the same as the original project. Something simple. It is not the sort of circuit that is used.
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That's true. And you can set the gain at 10, 100, or 10,000 and still have the exact same ouput.
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Okay nobody likes two opamps. Are you going to put the load here or there. A gain of 100 is better unless it's a power supply for microwaves.
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Yes, a gain of more than 1 is more desireable as the load current changes by a lot. A gain of 10 is very fine.