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Kevin Weddle

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Everything posted by Kevin Weddle

  1. I think at 1Khz, the capacitor could not completely charge in one cycle. No, that's not it. You have to make the resistance higher than the impedance of the capacitor.
  2. Something I noticed about voltage multipliers. I've never seen two equally charged capacitors reverse bias a diode. But as long as the capacitors are completely charged the diode is reverse biased.
  3. I know there is a simpler 15V to 45V voltage multiplier than the one I posted. It might be adequate. I won't bother posting that one.
  4. Wow this Windows 10 is great.
  5. Thanks guys. I love to hear you.
  6. They always conduct. No matter what. These two circuits are different. Resistors don't clamp a voltage. The voltages halve, halve, and halve again until Vp. ac.pdf
  7. The other equation is Xc - Xl. So a series LRC is only inductive or capacitive.
  8. In the quation v = L di/dt. The voltage goes up and the current goes up. In the equation i = C dv/dt. The voltage goes up and the current goes up.
  9. The only addition I'll add to my post is the current of the capacitor must at least be C dv/dt.
  10. Capacitor's pull current through a resistance. Then you have voltage momentarily.
  11. I went ahead and built this circuit today. The input resistor voltage changed very little. The output transistor voltages changed quite a bit.
  12. The schematic shown has a gain of 10. I changed the gain to 10,000 in this circuit. I don't know how unstable that would make it. I guess I'll have to match the opamp and output transistors.
  13. There is this 0-30v power supply. It's okay. Opamps need a higher power supply voltage because of the complexity of the circuit.
  14. The serialcom is a standard USB. So I guess it doesn't matter. It may be different from the more common computer power supply.
  15. I've got a computer with an external DC power supply. Does this affect the serialcom connection?
  16. Here is a good 3A 0v-30v power supply.
  17. Yes, maybe the transistors should be in the negative feedback loop of the opamp. But this circuit has to have similar function over much of the operating range. I know the impedance of 200k looks higher than the transistor impedance. But the voltage is relatively the same.
  18. No Hero99, that gain of 10 circuit is the same as the original project. Something simple. It is not the sort of circuit that is used.
  19. That's true. And you can set the gain at 10, 100, or 10,000 and still have the exact same ouput.
  20. Okay nobody likes two opamps. Are you going to put the load here or there. A gain of 100 is better unless it's a power supply for microwaves.
  21. Yes, a gain of more than 1 is more desireable as the load current changes by a lot. A gain of 10 is very fine.
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