j37prakash Posted August 2, 2011 Report Share Posted August 2, 2011 I need to design a circuit to switch on a warning lamp or sound a hooter when a door is opened and the reed switch is activated by the magnet. I have herewith attached the circuit diagram of the test setup. My problem is that the reed switch fails within a few (3 or 4) operations though the current measured is in very small units. Kindly advise me how to go about it to solve the problem. Quote Link to comment Share on other sites More sharing options...
Hero999 Posted August 2, 2011 Report Share Posted August 2, 2011 I assume you're using 110VAC, the DC is a typo?Even if the steady state current is low, a large current will flow for a short time when the capacitor charges which is probably what's causing the switch to fail. Quote Link to comment Share on other sites More sharing options...
j37prakash Posted August 3, 2011 Author Report Share Posted August 3, 2011 Oh I see Hero999! Then what should I use to substitute the circuit ? Pls explain Quote Link to comment Share on other sites More sharing options...
Hero999 Posted August 3, 2011 Report Share Posted August 3, 2011 Have you tried putting the reed switch on the 24VDC side? Quote Link to comment Share on other sites More sharing options...
hotwaterwizard Posted October 29, 2011 Report Share Posted October 29, 2011 Have you tried putting the reed switch on the 24VDC side? Quote Link to comment Share on other sites More sharing options...
hotwaterwizard Posted October 29, 2011 Report Share Posted October 29, 2011 If worst comes to worst add a relay triggered by the reed switch, Quote Link to comment Share on other sites More sharing options...
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