help with IR2110 chips

[Alec_t]

what about my 7 ohm coil that produces 14 volt ac and 28v dc

At what wheel rotation rate? Are we talking real life or simulation? Is that 14V peak or RMS? How is the coil producing DC?

I don't get what you mean by this?

Your fan (the inverter load) needs 15W of power to run at its rated speed.
No inverter is 100% efficient; 85% is more typical. So the needed input power to an 85% efficient inverter would be 15W x 100%/85% = 17.6W.

is it possible to add the outputs of the coils?

If you put in-phase coils in series then their output voltages will add; but so will their impedances, hence no current increase. If you put them in parallel then their currents will add but their voltages won't. The problem is that you need a power increase.

 

[Maglatron]

600 rpm real life

If you put in-phase coils in series then their output voltages will add; but so will their impedances, hence no current increase. If you put them in parallel then their currents will add but their voltages won't.

so no power gain?
the 28 volts is with the 7 ohm coil output through the rectifier that is still in the configuration I had it before in the image below

 

[Maglatron]

this is not a good reflection of what is happening in real life because in real life the DCvolts come to 28volt

 

[Maglatron]

so the simulation does not reflect whats going on, the voltage reaches 28volt on the meter for the 40Hz I did 600 / 60 = 10 and the * by the number of north poles (on one side), 4, = 40Hz, can you figure out the anomoly ?

 

[Maglatron]

Your fan (the inverter load) needs 15W of power to run at its rated speed.
No inverter is 100% efficient; 85% is more typical. So the needed input power to an 85% efficient inverter would be 15W x 100%/85% = 17.6W

so why does the average power dissipation = 3.4watt? and not 18watt

 

[Maglatron]

If you put in-phase coils in series then their output voltages will add; but so will their impedances, hence no current increase. If you put them in parallel then their currents will add but their voltages won't. The problem is that you need a power increase.

wait using two coils must increase power because there are two of them!! rather than one

 

[Maglatron]

could it be resonating?

 

[Maglatron]

this is the meter I used

https://www.amazon.co.uk/KAIWEETS-Professional-Autoranging-Capacitance-Continuidad/dp/B07Z398YWF/ref=pd_day0fbt_img_d_sccl_1/262-5612633-3920426?pd_rd_w=tJl8P&content-id=amzn1.sym.bfe06781-69ca-4a3a-9842-e535d2f2ae0e&pf_rd_p=bfe06781-69ca-4a3a-9842-e535d2f2ae0e&pf_rd_r=7PAN781ET9TAPH28A7BZ&pd_rd_wg=hPtkx&pd_rd_r=e5bdd7a5-968a-48cd-860a-acdb399ab93c&pd_rd_i=B07Z398YWF&psc=1

 

[Alec_t]

so why does the average power dissipation = 3.4watt? and not 18watt

Because a lot of voltage is dropped across the internal resistance of the coils, so power is wasted in heating up the coils.

the 28 volts is with the 7 ohm coil output through the rectifier that is still in the configuration I had it before in the image below

That is not the same configuration as I suggested originally. You have connected both terminals of V1 to the diodes.

so no power gain?

There is power gain, but not enough.

so the simulation does not reflect whats going on

You are not using the voltage-doubling arrangement I suggested originally.

Edit:
The post #448 arrangement doesn't provide voltage doubling, but would provide voltage addition if diodes D3 and D4 were removed.
However, because coil pairs 1 and 2 are not in phase their voltages partly cancel during parts of the wheel cycle.

 

[Maglatron]

no I didn't understand it properly but this is the measurement of one coil, can you post again how you suggested please I'm getting confused, or tell me which post number it was, thanks

 

[Maglatron]

from what I understood the rotary generator that you modelled was to half the resistance and double the current

You are not using the voltage-doubling arrangement I suggested.

or am I missing something, I only half understand whats going on in that spice model winding another coil today and am going to fit it, then we have two coils to work with that are identical and in phase

 

[Maglatron]

is this what you meant

 

[Alec_t]

Yes, that's what I meant for voltage addition/doubling. But remove R1, since V1 and V2 include series resistance.
Your circuit assumes V1 and V2 coil voltages are in phase, whereas my post #448 one has coil pairs with a phase shift.

 

[Alec_t]

Just running some numbers:
If the max voltage from your 7 Ohm coil is 14V and we assume its waveform is sinusoidal then its RMS voltage is 14 x root 2, = ~10V.
The maximum power it can deliver would be to a 7 Ohm load, so the current would be 10V/(7+7) Ohms = 0.714A, the voltage across the load would be 5V, and the power to the load would be 5V x 0.714A = 3.6W.
So to provide 18W for a fan it looks like you would somehow need to combine the power outputs of 18/3.6 = 5 coils (at least) with a similar output.
You might be able to get a higher per coil output with a more efficient magnetic circuit, e.g. by the addition of back-iron for the coils to minimise magnetic reluctance, but this would mean a major alteration to your generator.

 

[Maglatron]

5 in total? might be do able

 

[Maglatron]

so if I get 6 on then I'll be safe and also do you think I should mitigate the shift in phase? I'll be using 10 magnets

 

[Maglatron]

so I'm buying more of the copper wire and they don't have any 0.7mm they do have 0.724 and 0.574 what would you get?

 

[bertus]

Hello,

Thinner wire would have a higher resistance.

Bertus

 

[Maglatron]

so what is better 123meters of 0.724 or 195meter of 0.574

 

[Maglatron]

they dont have the same ones in stock that I bought last time!