help with IR2110 chips

[Maglatron]

so I've calculated the inductance by this equation L = Z/2pi*f
f is 50Hz
Z is impedance and the resistance is roughly 15% less than impedance so my coils have resistance of 2.5ohm and the inductance for it is 9.36mH
I'm using a step up transformer
so the primary resistance is 0.1ohm and the inductance works out to be 0.376mH
secondary resistance 3ohm inductance 11.24mH
I want to add the inductance to the 10volt ac supplies
also put the values for the transformer in and the resistances for the 10volt ac supplies and the output is not of the desired

 

[Alec_t]

I can't believe your L5 coil inductance is only a few nanoHenries!

 

[Maglatron]

so I measured the resistance's which the internet says is 15% lower than impedance Z and L = Z /2pi*f
f is 50hz and doesnt mH mean milli H
I can't even find L5
as far as I can tell there're L1 L2 L3

 

[Maglatron]

soo what are your thoughts on this? please help!!!

 

[Maglatron]

stuck two cores in the first set of two coils, they're made of ferrite welding rods with the flux crumbled off, trolley works like a charm!

 

[Maglatron]

so measured the resistance again today the 230volt side is 3ohm and the 40volt side of the transformer is 0.2ohm there was four wires black yellow orange and red red to black = 0.4ohm so I paralleled then with the yellow and orange to reduce the resistance whilst keeping the same turn ratio!! clever eh measured again the power coil, two out of three meters says 3.2ohm the other says 2.5ohm

 

[Maglatron]

can you get back to me please? thanks

 

[Alec_t]

I can't even find L5

Top left corner

f is 50hz

? Your sim shows 128Hz.
Your power coil array needs a ground connection.
The sim needs a run time of more than 1 sec.

 

[Maglatron]

so the power sources are 10volt and the wheel turns 8times a second and there are 16 magnets
8 * 16 is 128Hz
the inverter is supposed to invert the DC that come from the coils the diode and the smoothing cap, to invert that DC to an AC voltage, and that is where the 50Hz comes from - the pulses. I think I gotten a little confused with the frequencies and I still can't find the L5 in the top corner, where am I supposed to be looking because I really want to find it? BUT I do think that the 50Hz is correct for the transformer calculation!

 

[Maglatron]

Your power coil array needs a ground connection.

what is the power coil array? I think that it's already grounded if you meant the 8 power coils/supplies
could you do a mock up in spice of how to do it please, thanks
or even explain or put rings around the places that need looking at! thanks
I took the square root of both the 11.24 and 0.376 corresponding answers 3.3526 and 0.613 and that ratio is near enough 4 : 23 which is correct my transformer is 40 : 230
not sure what I am doing wrong
and how do I add inductance to the coils?? please, thanks

 

[Alec_t]

You had inductances, correctly added in series with the voltage sources (coils), in the asc file you posted previously.
In case you've over-written it I'm attaching it here.

 

[Maglatron]

oh ok that L5!! so is that wired up correctly because this image looks wrong to me surely it should be more voltage!!??!!

 

[Alec_t]

surely it should be more voltage!!??!!

It would be if the bottom of that set/array of coils had a connection to ground.
But the reactance due to all those coil inductances forms a voltage divider with the load they're driving, so the voltage across the load is lower than you're hoping for.
Edit:
As the coil voltages are being only half-wave rectified, that's another reason for low output.

 

[Maglatron]

there is a ground if you look closely, but how do I full rectify it? I set the coils to 3.2ohm. and corrected that top left one
If the coils are 3.2ohm and that is 15% less than the impedance, then the impedance is 3.76ohm
3.76 / 2 * 3.14152 * 128 = L = 4.68mH
so now I have set the inductances to 4.68mH and the coils to 3.2ohm

next: how to full wave rectify
thanks for your help

 

[Alec_t]

Since all eight coils are nominally the same you could sim the combination like this:

The contents of a dotted rectangle represent four coils in series. Rload is arbitrary here.

 

[Maglatron]

cool that is good

 

[Maglatron]

so how do you hook it into the IR2110 inverter circuit? thanks

 

[Alec_t]

Use the inverter circuit as a replacement for Rload.
I think reality will differ from the sim significantly because (a) the coils are not identical, (b) they may be slightly out of phase, (c) I suspect they have greater inductance than the values you are currently using in the sim.

 

[Maglatron]

yep I'm going to get inductance meter when I get paid also the coils are near identical I'm now using edaboards too a guy on there said
"some points:
1) if the supply of the logic chip (that generates the signal) is 3.3V ... then the signal itself will always be less!
2) to me it seems the V_IH for 5.0V supply is about 3.5V according the diagram. Mind: vertical it´s 3V/div
3) if your weigth is 80kg ... and you go on a bungee jump ... and they say the maximum the rope can handle is 80kg .... would you do the jump?

Some hobbyists may have no problem with it...

But for me - as a designer for reliable industrial electronics - this is an absolute no go.
One has to consider that the supply voltage (3.3V) will have initial tolerance, thermal drift and drift with load. So in worst case it may be 15% to 20% less than nominal.
And also the supply voltage (5V) and the thresholds of the IR2110 will drift (to more positive in worst case)

If you get 3.3V (nominal supply voltage) signals and you want to feed the IR2110 (5V supplied) .... I recommend to use an 74HCTxxx logic device (supplied with 5V) as level shifter."
what are your thoughts on that Mr Alec_t
I have a 75HCT chip to hand here is the circuit that I have right now forgetting the coils and such lets just say that its a 12v source, so, when I set the VDD to 5volt the circuit doesn't work if the signal is not also 5volt but in reality I want the signal voltages to be approximately 3.3volt because that is the max that it should be!! thanks I know that it is stupid but this is correct right

 

[Maglatron]

but let me say you guys have helped me no end and my loyalties lie here, just sayin