OK. You won't be able to measure that resistor; normal multimeters can't measure resistances higher than 20 megohms. You can measure it using the 120V rail but you'll have to do a bit of work.
First, check that your multimeter has an input resistance of 10 megohms when measuring voltage. This is normal and standard for modern digital multimeters.
1. Remove R13 from the board.
2. Disconnect off-board Q1 from the HVPS board, to disable the HVPS circuit completely (very important).
3. Using alligator clip leads, connect one end of the R13 resistor to the +120V test point, and connect the other end of the resistor to the positive probe of your multimeter. Connect the negative probe of the multimeter to the 0V rail or chassis of the oscilloscope.
4. Set the multimeter to a 50V or higher DC voltage range.
5. Power up the scope and look at the multimeter reading.
If the R13 resistor is OK, you should measure about 30V and the measurement should be fairly stable (assuming the 120V rail is stable).
If you're interested, here's how I calculated that voltage.
When you connect two resistances (the R13 resistor and the multimeter's input) in series, their resistances add. The total resistance will be 30 megohms plus 10 megohms, which is 40 megohms.
Ohm's Law says I = V / R, where I is current in amps; V is voltage in volts, and R is resistance in ohms. With 120V across a 40 megohm resistance, the current should be 120 / 40,000,000 which is 0.000003 amps, or 3 µA (microamps).
Ohm's Law can be rearranged to V = I R. When that's applied to the multimeter only, V (voltage) is 0.000003 amps multiplied by 10,000,000 (the input resistance of the multimeter), which is 30 volts.
Therefore there should be 30 volts across the multimeter and that is what you should measure.
If the voltage is badly wrong, especially if it's too low, or if it jumps around constantly, you can replace it with nine 3.3 megohm resistors in series. Solder them together in a long string, and mount them off the board. Use metal film resistors.