nwaste Posted October 23, 2005 Report Share Posted October 23, 2005 i need a counter which have more stages than one 4017 (10 stages). I was thinking is is possible to build "one" counter from two or more 4017 (when first finish counting of 9 stages than 2nd one starts to counting new 9 stages...)Please hel with some circuit Quote Link to comment Share on other sites More sharing options...
Guest Alun Posted October 23, 2005 Report Share Posted October 23, 2005 Simple, build two 4017 counters, connect the input of the second one to the last output of the first one. Quote Link to comment Share on other sites More sharing options...
Staigen Posted October 23, 2005 Report Share Posted October 23, 2005 HiAlun, if i remember right it is not that simple, some gates was also needed, maybee i'm wrong, please correct me then.//Staigen Quote Link to comment Share on other sites More sharing options...
Guest Alun Posted October 23, 2005 Report Share Posted October 23, 2005 I don't think so, just connect the last output (9 I think) to the input so another 4017 and it will count every 10 pulses, so you'll have a 0 to 100 counter, is this what you wanted? Quote Link to comment Share on other sites More sharing options...
audioguru Posted October 23, 2005 Report Share Posted October 23, 2005 It is done like this: Quote Link to comment Share on other sites More sharing options...
Staigen Posted October 23, 2005 Report Share Posted October 23, 2005 Yapp Audioguru, thats the way it was, i belive :)!//Staigen Quote Link to comment Share on other sites More sharing options...
MP Posted October 23, 2005 Report Share Posted October 23, 2005 No. Alun is correct (except that 2 4017s will not give 100 counts). To get a continuous count, you simply gang up the 4017 counters. The last count is used to start the next 4017 and so on...MP Quote Link to comment Share on other sites More sharing options...
Staigen Posted October 23, 2005 Report Share Posted October 23, 2005 Show us MP, with a schematic! :)//Staigen Quote Link to comment Share on other sites More sharing options...
Guest Alun Posted October 23, 2005 Report Share Posted October 23, 2005 MP is correct, I was wrong about the 100 counts part although you can make a /100 counter it won't have 100 outputs it'd have two 0-9 outputs, one representing 10s and the other units. Quote Link to comment Share on other sites More sharing options...
nwaste Posted October 23, 2005 Author Report Share Posted October 23, 2005 Ofcourse is not that simple. You know what happend when you connect last stage of 1st one to first stage of 2nd one? First IC gonna count normaly, but the 2nd one will run 10 TIMES SLOWER, cuz the 1st one will only triger 2nd one when 1st one is on the last stage (that's why 10 TIMES). So, Please help me! Quote Link to comment Share on other sites More sharing options...
Guest Alun Posted October 23, 2005 Report Share Posted October 23, 2005 See audioguru's post.The only thing is two 4017s give you 17 outputs, if you want 20 you'll need to use three and connect the reset to the output 3 of the last counter (remember output 0 isn't used). Quote Link to comment Share on other sites More sharing options...
audioguru Posted October 23, 2005 Report Share Posted October 23, 2005 Bill Bowden recently posted this 18-stage sequencer on his site. It is complete with all the good stuff like power-up reset: Quote Link to comment Share on other sites More sharing options...
Guest Alun Posted October 23, 2005 Report Share Posted October 23, 2005 If you use a 4011 you could save yourself the 555, four diodes and two resistors.Edit:Clould you please provide the origional source Quote Link to comment Share on other sites More sharing options...
ante Posted October 23, 2005 Report Share Posted October 23, 2005 Hi Alun,If you enter “Bill Bowden” in Google you end up with this: http://ourworld.compuserve.com/homepages/Bill_Bowden/homepage.htmI thought everyone knew this guy? ;D Quote Link to comment Share on other sites More sharing options...
audioguru Posted October 23, 2005 Report Share Posted October 23, 2005 If you use a 4011 you could save yourself the 555, four diodes and two resistors.No, A 4011 has NAND gates. You need a 4081 or 74C08 which have AND gates, and you would still need an oscillator.I've never tried making a Wien-bridge oscillator from an AND gate or non-inverting buffer, it might work since they have lotsa gain. ;D Quote Link to comment Share on other sites More sharing options...
Guest Alun Posted October 23, 2005 Report Share Posted October 23, 2005 Silly me getting my NANDs and ANDs mixed up!I think an oscilator made with AND gates might latch up due to the high gain, I wonder if a phase shift oscillator is possible using lots of resistors and capacitors. ;D Quote Link to comment Share on other sites More sharing options...
audioguru Posted October 23, 2005 Report Share Posted October 23, 2005 I think an oscilator made with AND gates might latch up due to the high gain, I wonder if a phase shift oscillator is possible using lots of resistors and capacitors.I guess the gain of an AND gate is so high that it would be a nightmare to try to bias the thing to a linear region. Quote Link to comment Share on other sites More sharing options...
steven Posted March 11, 2006 Report Share Posted March 11, 2006 :) Quote Link to comment Share on other sites More sharing options...
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