upsurt Posted May 19, 2007 Report Posted May 19, 2007 Hi,I have to analyse this circuit and know what it does...I think its an transconductance amplifier...but I need to know how to find the transconductance gain of it....the circuit its int the following link Quote
AN920 Posted May 19, 2007 Report Posted May 19, 2007 You think? What do you understand under transconductance? Quote
upsurt Posted May 19, 2007 Author Report Posted May 19, 2007 Im studying realimentation in electronic circuits, I know that for have transconductance gain the circuit have to be of serie-serie type....I have V in the entry and I in the out of it.To have a transfer function of it I divided in two parts: A=>the amp-op and the part of diodes and transistors and 2) Beta=>the two Resistances of 1kohm. This way I think I can calculate the transfer function of the circuit to a form A/(1+Beta*A)In the diodes and transistor part the gain it Quote
audioguru Posted May 20, 2007 Report Posted May 20, 2007 The schematic is small and is a very fuzzy JPG file type. It would be much clearer if it was made as a GIF or PNG file type.I can hardly see the part numbers. I cannot see the inverting and non-inverting symbols on the opamp.Why did you post the schematic "over there"? Please attach a clear schematic to your reply here. Quote
audioguru Posted May 20, 2007 Report Posted May 20, 2007 Thank-you, Upsurt.Your new schematic is very clear as a GIF file type. But it was huge so I reduced its size, cropped it and made some of its dotted lines solid lines.I don't think the resistor in series with the load is needed. The voltage gain of the amplifier will be 1 when the load resistance is very low.I also don't think the capacitor is needed because the output transistors are emitter-followers with a very wide bandwidth, very low phase shift and no voltage gain.I changed the 47k feedback capacitor to 100k so that the output impedance of the amplifier can be higher. Quote
upsurt Posted May 20, 2007 Author Report Posted May 20, 2007 Thanks for the help audioguru! :)Where I have more difficult anaslysing the circuit its in the opamp part... I dont know how to calc the transfer function of it ??? Quote
audioguru Posted May 21, 2007 Report Posted May 21, 2007 The opamp has an extremely high input resistance because its input transistors are FETs. It has an open-loop voltage gain of typically 200,000 so the resistors set the closed-loop gain with their negative feedback. Quote
AN920 Posted May 21, 2007 Report Posted May 21, 2007 I made the 1k resistor on the inverting input R3 because you have multiple R2'sFrom writing the nodal equations for the opamp and solving:Without the capacitor across the feedback resistor G(s) = (R2 + R3)/R3 = 48With the capacitor added G(s) = (R2 + R3 + R3.C1.R2.s)/(R3 + R3.C1.R2.s)Imput impedance 1k, output impedance ~ 24m Ohm Quote
upsurt Posted May 21, 2007 Author Report Posted May 21, 2007 Thank you audioguru and AN920 for the help :) Quote
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.