Resistance of Primary Winding of a Transformer

chopnhack

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Is the resistance of the primary winding of a transformer responsible for preventing a short? I was thinking about how we plug our appliances into mains voltage and typically its reduced via a step down transformer. The transformer itself is simply a primary and secondary winding. The winding itself is a closed loop of wire! Essentially a short circuit. So why does it work. The only thing I could puzzle out was that the wire itself offers enough resistance? Can someone explain this to me. I looked on Google and http://www.electronics-tutorials.ws/transformer/transformer-basics.html
but didn't find an exact explanation. I searched Google with "does the resistance of wire in the primary coil prevent a transformer from shorting out"

Regardless, just thinking it through, if a coil of wire would have less than 6 Ω (in the states most plugs are rated for 15 or 20a so 120v/6Ω = 20a) the breaker would trip.
 

Gryd3

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Is the resistance of the primary winding of a transformer responsible for preventing a short? I was thinking about how we plug our appliances into mains voltage and typically its reduced via a step down transformer. The transformer itself is simply a primary and secondary winding. The winding itself is a closed loop of wire! Essentially a short circuit. So why does it work. The only thing I could puzzle out was that the wire itself offers enough resistance? Can someone explain this to me. I looked on Google and http://www.electronics-tutorials.ws/transformer/transformer-basics.html
but didn't find an exact explanation. I searched Google with "does the resistance of wire in the primary coil prevent a transformer from shorting out"

Regardless, just thinking it through, if a coil of wire would have less than 6 Ω (in the states most plugs are rated for 15 or 20a so 120v/6Ω = 20a) the breaker would trip.
Remember it is also an inductor, and you are feeding an AC voltage into it which will (depending on the value of course) further increase the resistance seen by the Voltage Source.
It would also have an additional coil magnetically coupled with the primary. I'm not too skilled at calculating the exact effects of this, but I know it changes things ;)
 

Arouse1973

Adam
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Remember it is also an inductor, and you are feeding an AC voltage into it which will (depending on the value of course) further increase the resistance seen by the Voltage Source.
It would also have an additional coil magnetically coupled with the primary. I'm not too skilled at calculating the exact effects of this, but I know it changes things ;)

Yes correct. Reactance is the reason for this and a small resistance also.
Adam
 

chopnhack

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Remember it is also an inductor, and you are feeding an AC voltage into it which will (depending on the value of course) further increase the resistance seen by the Voltage Source.
It would also have an additional coil magnetically coupled with the primary. I'm not too skilled at calculating the exact effects of this, but I know it changes things ;)
Thanks G, that helped me do a better search. That reactance keeps popping up! I found this site and based on the calculations there for 120v, 60hz - 21:1 turn ration would theoretically produce a step down to 5.7vac. The reason it wouldn't trip the breaker is the primary reactance is listed as ~360Ω so only about 0.3A. The reactance/resistance prevents the "short" I assume.
 

Arouse1973

Adam
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Is the resistance of the primary winding of a transformer responsible for preventing a short? I was thinking about how we plug our appliances into mains voltage and typically its reduced via a step down transformer. The transformer itself is simply a primary and secondary winding. The winding itself is a closed loop of wire! Essentially a short circuit. So why does it work. The only thing I could puzzle out was that the wire itself offers enough resistance? Can someone explain this to me. I looked on Google and http://www.electronics-tutorials.ws/transformer/transformer-basics.html
but didn't find an exact explanation. I searched Google with "does the resistance of wire in the primary coil prevent a transformer from shorting out"

Regardless, just thinking it through, if a coil of wire would have less than 6 Ω (in the states most plugs are rated for 15 or 20a so 120v/6Ω = 20a) the breaker would trip.

Right John you can work this out. Do an example, find a transformer or make it up, which you know the unloaded primary current. Then work out the inductance by using XL=2×pi×f×L. f being your mains frequency. XL being the AC resistance.
Adam
 
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chopnhack

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Is L assumed to be 1 henry? If so I get 376Ω as the primary reactance.
 

Colin Mitchell

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I have explained how a transformer works on my site Talking Electronics.com.
The main reason why the transformer does not "blow a fuse" is because it produces a "back voltage" of nearly 95% - 99% of the supply voltage and thus the actual voltage entering the transformer is just 1v to 5v and at this voltage, the current-flow is not very high.
 

chopnhack

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I have explained how a transformer works on my site Talking Electronics.com.
The main reason why the transformer does not "blow a fuse" is because it produces a "back voltage" of nearly 95% - 99% of the supply voltage and thus the actual voltage entering the transformer is just 1v to 5v and at this voltage, the current-flow is not very high.
Thanks Colin, off I go to search your site, many thanks :)
 

Colin Mitchell

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Here is something I have on my website as an answer to an argument with a moderator on a forum:


HOW THE TRANSFORMER WORKS
The first item you need to study is the TRANSFORMER.
It's the main component of the power supply and appears to be the simplest. But there is a lot to know about how it works and the main reason why it is present in a power supply has NEVER been explained.
Of course it provides ISOLATION and converts a high voltage to a low voltage and can deliver a current higher than the mains will deliver, but all this can be done without the magnetic core - that makes the transformer so heavy.
So, why is the core needed?
Let's explain it this way.
If you get a length of wire, say 120 metres, it will have a resistance, say 120 ohms and if you connect it to a 240v AC supply, a current of 2 amps will flow, according to Ohm's Law.
For this discussion, the voltage must be AC. In other words it must be alternating, such as from the mains, at a frequency of 50 or 60 times per second. A transformer only works on alternating voltage - commonly called alternating current.
This will produce a wattage of 2 amps x 240 volts = 480 watts and the wire will get very HOT.
But if we wind the wire on a plastic pipe with lots of layers, to produce a closely bunched coil, each turn will produce magnetic flux and this flux will cut all the other turns of the coil.
As the flux cuts each of the other turns, it produces a tiny voltage in each turn that is opposite to the incoming voltage.
It might produce a "back voltage" of say 20 volts and so the effective incoming voltage is 240v - 20v = 220v. This means less current will flow and the coil will not get as hot.
If we now wind another coil of half the number of turns (or any number of turns) and place it beside the first coil and connect the ends of this coil to a low value resistor, we will see what happens.
As the applied voltage increases, the magnetic flux from the primary winding increases and cuts the turns of the new coil. Voltage is produced in each turn and this is added by each turn and appears on the output leads. This voltage allows a current to flow in the LOAD resistor and the magnetic flux from the primary winding is converted to current in the secondary winding and thus it is not available to cut the turns of the primary winding. In other words, all the flux produced by the primary is "used up" by the secondary winding.
If the LOAD resistor is a very low value, the secondary winding will be able to accept and convert all the flux it receives and convert it to current.
But what controls the current in the primary?
The current flowing in the secondary produces magnetic flux and this flux produces a back voltage in the primary as the effective forward voltage is reduced. This reduced voltage allows a smaller current to flow so that the total watts delivered by the primary is equal to the watts required by the LOAD.
This means the two coils will work perfectly without the need for a magnetic core.
But if the load resistor is a higher value, the secondary winding will not require a high current and it will produce less flux and the back voltage will not be as high. Thus the forward voltage increases and produces a higher current in the primary winding and the winding will get hot.

So, what is the purpose of the magnetic core?
When the secondary is not accepting all the magnetic flux produced by the primary, the excess flux passes into the magnetic core and and the tiny metal particles in the core produce a current just like the secondary winding and this current produces magnetic flux that opposes the flux produced by the primary winding. This reduces the effective incoming voltage and thus the current in the primary winding is reduced.
In other words, the core takes the excess flux and converts it to an opposing voltage to prevent any increase in primary current, over that required by the secondary winding.
If we take this effect to the extreme, and remove the secondary load, ALL the flux produced by the primary winding is passed to the core and the core sends back an opposing voltage that can be as high as 99% of the incoming voltage. This is why a transformer will consume very little current when the output is not connected.
Not loading the secondary is EXACTLY the same as removing the secondary winding and this fact has escaped many moderators on the web, who have not studied the concepts of the operation of a transformer.
This fact has never been covered in any text books and that is why many engineers do not have a firm understanding of the concepts.

. . . . more on my website . . . . . .
 

chopnhack

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HOW THE TRANSFORMER WORKS

. . . . more on my website . . . . . .

images

Can we get a link to the website and a sticky to this explanation??
 

chopnhack

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I have so many transformer explanations on my website, it took me 30 minutes to find the relevant section. I have posted it above.
Colin, thank you, but the linked material is just advertising. I think you may have inadvertently selected the wrong link. Thank you for taking the effort to find the section, I hope you can spare us another moment to fix the link!
Thanks again :D
 

Colin Mitchell

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That's weird, look at post #11, for me it shows up as:

*REMOVED*

I am very clever. I am multi-talented. I can answer your question and provide an answer to the best PCB maker in China, AT THE SAME TIME ! I have tried lots of PCB makers and they are all a rip-off. I pay $15.00 for 100mm x 100mm 10 boards. double sided. One supplier wanted $420 USD !! I get 2 panels done each week. There is a constant stream of deliveries. The only problem is you have to keep accurate records and files and trays to keep the hundreds of projects - otherwise you forget what you are designing.
I learnt to breathe in and out and chew gum at the same time. Now I can do both at once.
And I can find the answer to your transformer question on my website in less than 30 minutes.
 
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chopnhack

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I just had very good service from smart-prototyping in China. The board looks to be very good to my novice eyes. More on that when it gets in ;-) Very reasonable for a double sided 2oz. board.
 

chopnhack

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$28.66 1.6mm, HASL, soldermask, 2 oz. copper, qty 10 of 10x10, 100% E-tested
 
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