flippineck
- Sep 8, 2013
- 358
- Joined
- Sep 8, 2013
- Messages
- 358
I have two identical Chinese solar panels, which both claim to have "inbuilt diode prevent the reverse of charging situation".
Open circuit voltage quoted as around 19V, quoted current around 5A.
Let's say I connected the two in series, and illuminated both with bright sunshine sufficiently strong to achieve the maximum output as per spec sheet.
If I then connected a voltmeter across the two, I would expect to see something approaching 38V. And if I connected an ammeter, something like 10A.
If I then blacked out one panel completely so it was in 100% darkness, leaving the other in the sunshine, would I get 19V and 5A?
Or, would the dark panel cause a significant dimunition of the power flow?
panels are similar to:
http://www.ebay.co.uk/itm/Biard-100...119699?pt=UK_Gadgets&var=&hash=item232d13ad93
Open circuit voltage quoted as around 19V, quoted current around 5A.
Let's say I connected the two in series, and illuminated both with bright sunshine sufficiently strong to achieve the maximum output as per spec sheet.
If I then connected a voltmeter across the two, I would expect to see something approaching 38V. And if I connected an ammeter, something like 10A.
If I then blacked out one panel completely so it was in 100% darkness, leaving the other in the sunshine, would I get 19V and 5A?
Or, would the dark panel cause a significant dimunition of the power flow?
panels are similar to:
http://www.ebay.co.uk/itm/Biard-100...119699?pt=UK_Gadgets&var=&hash=item232d13ad93