Kevin Weddle Posted October 15, 2004 Report Share Posted October 15, 2004 The derivative of the sin 2X is the cos 2X. Correct. I was looking into the RMS and found some interesting stuff. If you take the RMS value and square it you get the average of the equation squared. Quote Link to comment Share on other sites More sharing options...

surajbarkale Posted October 20, 2004 Report Share Posted October 20, 2004 Dear Kevin,RMS = Root Mean SquareIt is the root of the average of the sum of squares (sounds kool ;D)see http://mathworld.wolfram.com/Root-Mean-Square.html if u like equations.& btw derivative of sin2x is 2cos2x Quote Link to comment Share on other sites More sharing options...

Kevin Weddle Posted October 21, 2004 Author Report Share Posted October 21, 2004 I think you are wrong about that. If you take 90 degrees for example you get the derivative of sin90=cos90. Therefore the derivative of the sin 2x=cos 2x. Quote Link to comment Share on other sites More sharing options...

surajbarkale Posted October 25, 2004 Report Share Posted October 25, 2004 What a wonderful proof :o d/dx(sin2x) = d/dx(sin2x) * d/dx(2x)= 2 * cos2xremember the chain rule for derivative ??? http://www.math.hmc.edu/calculus/tutorials/chainrule/http://people.hofstra.edu/faculty/Stefan_Waner/RealWorld/trig/trig3.html Quote Link to comment Share on other sites More sharing options...

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