thx guru the fringe problem is fix reason was a ic741 was burned
Do you mean that the problem where the output voltage was always -0.5V is fixed because a 741 opamp was burned?
from original circuit U3 output voltage is about 30VDC and U2 output voltage along with the supply voltage change isn't correct?
I don't know what you are asking. It is normal for the output voltage of U3 to be +30V when it is not regulating the current. The output voltage of U2 is about 1.5V higher than the project's output voltage.
the ripple can check with electric meter ? if the digital electric meter show the voltage is fix at 0.01xVDC mean low ripple ?
Ripple is not DC, it is AC at double the mains frequency. If the value of C1 is only 3300uF like in the original project then the ripple voltage on C1 is about 6V p-p (2.1V RMS) when the output current is 3A.
then the output of the project will also have ripple if its output voltage is more than about 22V at 3A.
this circuit have auto protect function ? mean when the output voltage is short circuit will have a signal ?what the function of D12 LED ? when it will light up ?
I explained the current regulation in my last post.
The max amount of output current is set by the current adjust pot. The current regulator reduces the output voltage so that the current is not more than the setting of the pot. When the current regulator is reducing the output voltage then it lights the warning LED.
when i supply to 20VDC + 2A the Q4 2N3055 is heat up too much can i use 2x 2N3055 like the new circuit for relief it heat up ? and the R7 also heat up quickly should i change to it 10W resistor ?
Your 2N3055 transistor has 33V on its collector and its emitter is 20V. Then it has 13V across it.
The amount of heat it is dissipating is 13V x 2A= 26W. It needs a heatsink big enough so that it does not get too hot when it dissipates 26W. A very big heatsink will allow it to dissipate about 70W but then it and the heatsink will be very hot.
The 0.47 ohm/5W resistor R7 has a current of 2A so it is dissipating 2A squared x 0.47 ohms= 1.88W.
A 5W resistor can easily dissipate only 1.88W. Space it up a little away from the pcb.