effenberg0x0 Posted December 8, 2009 Report Posted December 8, 2009 Hi Effenburg,thanks for the comparison that shows both almost the same.And yet very different from original design. Before I landed here at this board, I saw many blogs and websites in Portuguese, Spanish, Italian, other languages, in which people were building the original version and complaining about the results or building mixed versions, unaware of the correct parts list. Power supplies are obviously very popular with newbies like me - a first real project, primary need in the workbench.Let me ask you guys a couple more questions: - How does this PS compares to professional ones? They're very expensive! What do they have that this one doesn't?- From a more experienced point of view, what do you see as the weaknesses of this projects?- The original project mentioned adding voltmeter + current meter with LCDs through this project: http://www.electronics-lab.com/projects/test/022/index.html . Did you guys ever built this add-on? It seems doable, but soldering SMD components neatly is still hard for me. Shaky hands.Kind regards,Effenberg Quote
effenberg0x0 Posted December 8, 2009 Report Posted December 8, 2009 here is the circuit, the parts list are the same as such in the above post.....no change...u can start doing the circuit...Thanks karthikeid! Actually after submitting this project as my goal at the course, next 2 months will be 6 hours/day and 6 days/week of Malvino's book now... It's all theory, some use of eagle, for a while until they let us start building it. We must be able to describe each components behavior, analyze the circuit basically, predict output, etc before giving it a go...Thanks for the schematics!Regards,Effenberg Quote
audioguru Posted December 8, 2009 Report Posted December 8, 2009 The original project is a kit. The kit maker must get a lot of complaints of it not working properly, many parts getting too hot and poor reliability. Quote
effenberg0x0 Posted December 8, 2009 Report Posted December 8, 2009 OIC...Audioguru, do you believe it would be possible to build this project on a plastic case? Or is it too risky?When you people mention the heat generated, I am not sure how many degrees you are talking about.Thanks Quote
audioguru Posted December 8, 2009 Report Posted December 8, 2009 When the current is 3A then R7 dissipates 3A squared x 0.47ohms= 4.23W.Q2 dissipates as much as 2.3W when the output is 3A and is shorted.The output transistors dissipate a total of 117W when the output is 3A and is shorted.That is a lot of heat. Quote
effenberg0x0 Posted December 8, 2009 Report Posted December 8, 2009 OK, Thanks. I'm gonna try an aluminium case with a large heatsink and possibly a cooler/fan.Can I use thermal paste like Artic Silver? I come from IT, we use that on CPUs. Quote
redwire Posted December 8, 2009 Author Report Posted December 8, 2009 effenberg wrote:The original project mentioned adding voltmeter + current meter with LCDs through this project: http://www.electronics-lab.com/projects/test/022/index.html . Did you guys ever built this add-on? It seems doable, but soldering SMD components neatly is still hard for me. Shaky hands.Why don't you build the non SMD version that is linked to the above site. Original design page located here: http://elfly.pl/multimetr/multimetr_en.htmYes, several have built is successfully. I have a non smd LCD version working on mine. I'll post some pictures later. Quote
effenberg0x0 Posted December 8, 2009 Report Posted December 8, 2009 Redwire: Please post the pics, it helps a lot!Guys, I am having trouble finding C1 (12,000 UF / 63V electrolytic). I know I can use 3 caps, as you mentioned, but I haven't found 4,000 uf / 63V.I know Cx=Cn+Cn'+...+Cn'', in theory, but the units I have are 3,300uf/ 63V and 4,700uf / 63V.So using (2 x 4,700) + 3,300 I'll get 12,700... Is it ok?Thanks. Quote
audioguru Posted December 8, 2009 Report Posted December 8, 2009 A 12,000uf/63V capacitor is available in North America at Digikey or Newark.You can add smaller capacitors in parallel if you want but then their total cost is more.The capacitance can be higher then the project will work better. Quote
effenberg0x0 Posted December 8, 2009 Report Posted December 8, 2009 Thanks Audioguru. The problem is I have to use the pieces available at the course inventory. Redwire's 5A project suggests RS1506 (15A 600V) or GBJ2506 (25A 600V). They're also not available to me, so I am going for KBPC-3510 35A/1000V. Quote
Guest Enforcer83 Posted December 8, 2009 Report Posted December 8, 2009 In the Schematic posted by audioguru at the beginning of this topic, there is a 10V 10W Zener diode between the output of the Bridge Rectifier and the emitter of the PNP transistor. I am confused with its purpose. I have tried to analyze it using my circuit theory but have failed miserably, partially because I have always used regulators instead of diodes for voltage regulation. So, what is its purpose? A PSpice waveform would be very useful to help me visualize what is going on, if at all possible. Quote
audioguru Posted December 8, 2009 Report Posted December 8, 2009 In the Schematic posted by audioguru at the beginning of this topic, there is a 10V 10W Zener diode between the output of the Bridge Rectifier and the emitter of the PNP transistor. I am confused with its purpose. I have tried to analyze it using my circuit theory but have failed miserably, partially because I have always used regulators instead of diodes for voltage regulation. So, what is its purpose? A PSpice waveform would be very useful to help me visualize what is going on, if at all possible.The 28V transformer might be 30V without a load on the project. Then it makes an unregulated positive voltage of 41V plus a negative -1.3V supply for U1. The total of 42.3V is very close to the max total allowed voltage of 44V and heats the IC. So the 10V zener diode reduces the max voltage and shares in the heating. Quote
Hero999 Posted December 8, 2009 Report Posted December 8, 2009 It really isn't. I could order from Farnell but it would more expensive than all the other components (about 120USD!!). As I have to use the components they have at the course anyway, I selected 4,700uf+4,700uf+3,300uf = 12,700uf / 63V.Electrolytic capacitors are normally only made in E6 values, i.e. 10, 15, 22, 33 and 68 but some manufacturers only make E3 values i.e. 10, 22 and 47 which is why you're having problems finding 12,000 Quote
Guest Enforcer83 Posted December 9, 2009 Report Posted December 9, 2009 The 28V transformer might be 30V without a load on the project. Then it makes an unregulated positive voltage of 41V plus a negative -1.3V supply for U1. The total of 42.3V is very close to the max total allowed voltage of 44V and heats the IC. So the 10V zener diode reduces the max voltage and shares in the heating.Be patient with me on this. Power and power electronics are not my strong suit. Low voltage battery systems are.So you mean to tell me the Zener is adding 11V to the system. That does not make sense. Wouldn't the better option be to place say a 36V Xfmr with a no load rating of 38.52V in the system and connect the transistor, the resistor R19 and the V+ of the opamps to this rail instead? Even figuring a Voltage drop of 1.05V at 5A through a bridge Rectifier (GBJ10005 is my planned rectifier) you are still dealing with 37.47V. Yes it may be more expensive but at least the math seems logical.I think I need a tutor to help me relearn this area of Electrical Engineering. Doesn't help my circuit Prof. couldn't teach. Quote
audioguru Posted December 9, 2009 Report Posted December 9, 2009 So you mean to tell me the Zener is adding 11V to the system.No.A 28VAC transformer might be 30VAC without a load. Then its peak voltage is the root of two times 30V= 42.4V and the full-wave rectifier charges the main filter capacitor to +41VDC. IC U3 also has a negative -1.3V supply so its total would be 42.4V which is very close to its max allowed total voltage of 44v and it has a lot of heat.The 10V zener diode reduces its positive supply to +31V and reduces its heat.Wouldn't the better option be to place say a 36V Xfmr with a no load rating of 38.52V in the system ....Then the positive unregulated supply would be +53VDC and everything will blow up.Even figuring a Voltage drop of 1.05V at 5A through a bridge Rectifier ....When the project has a 5A load then the average current in the bridge rectifier is also 5A.But it conducts only on the peaks of the transformer's sine-wave for only maybe 10% of the time, so its peak current is 50A.It has two diodes conducting in series so its voltage drop is about 2V. Quote
Guest Enforcer83 Posted December 9, 2009 Report Posted December 9, 2009 I knew that pesky root 2 was going to come up and bite me in the arse one day. :-[Now I see whats happening.Edit:Like I said, AC power not my strongest area. Quote
effenberg0x0 Posted December 9, 2009 Report Posted December 9, 2009 >>A 28VAC transformer might be 30VAC without a load. Noob question: Why? Are you considering the AC power oscillation in the primary? Thanks,Effenberg Quote
audioguru Posted December 9, 2009 Report Posted December 9, 2009 >>A 28VAC transformer might be 30VAC without a load. Noob question: Why?Because the windings have resistance. The output voltage drops down to the transformer's rating only when it has its rated load.Test the output voltage of a 9V/200mA wall-wart. It is 9V only when it has a 200mA load but is 15V or more without a load due to the resistance of its windings. Quote
effenberg0x0 Posted December 9, 2009 Report Posted December 9, 2009 Audioguru, I am a little confused.I was thinking about Ohms law. If I = V / R and then V = I * R, decreasing the value of R would decrease the value of V, assuming constant I. Then why would the transformer voltage be higher without a load?Thanks,Effenberg Quote
Hero999 Posted December 9, 2009 Report Posted December 9, 2009 The transformer is not perfect and has an equivalent series resistance which drops the voltage when a current it drawn. Quote
audioguru Posted December 9, 2009 Report Posted December 9, 2009 If a 28V transformer is rated at 3A then it is made as a 30V transformer because the designer knows that its voltage will drop 2V due to the resistance of its windings.The cheap little 9V/200mA wall-wart is made as a 15V one because ..... (same thing). Quote
effenberg0x0 Posted December 10, 2009 Report Posted December 10, 2009 I did the tests (wall-wart). You are right.Another stupid one: I've been checking projects of other students. Some of them have a fuse. On the other hand, I could not find a single power supply project on the net that has a fuse. Where do you stand? Should there be a fuse?Also: It doesn't seem like eagle (last version) auto-track feature takes under consideration a decent space between tracks (potential capacitance?). Or does it? Quote
audioguru Posted December 10, 2009 Report Posted December 10, 2009 A fuse should be installed in series with the on-off switch in the mains wiring to prevent your home from being burned down if something in the project goes wrong.But I think England has a fuse in the electrical plug. Quote
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