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Total number of cartons = 700 . <br> (i) Let `E_(1)` be the event of choosing a carton having no defective bulb . Then , <br> P (choosing a carton having no defective bulb) <br> `= P(E_(1))` <br> = `("number of cartons having 0 defective bulb")/("total number of cartons")` <br> `= (371)/(700) = (53)/(100) = 0.53`. <br> (ii) Let `E_(2)` be the event of choosing a carton having defective bulbs less than 4 . then, <br> P (choosing a carton having defective bulbs less than 4) <br> `= P(E_(2))` <br> = `("number of cartons having defective bulbs 0 , 1 , 2 or 3")/("total number of cartons")` <br> `(371 + 162 + 55 + 49)/(700) = (637)/(700) = (91)/(100) = 0.91`. <br> Let `E_(3)` be the event of choosing a carton having defective bulbs more than 3 but less than 6 . Then , <br> P (choosing a carton having defective bulbs more than 3 , but less than 6) <br> `= P(E_(3))` <br> `("number of cartons having defective bulbs 4 or 5")/("total number of cartons")` <br> = `(41 + 15)/(700) = (56)/(700) = (8)/(100) = 0.08` . <br> (iv) Let `E_(4)` be the event of choosing a carton having defective bulbs 6 or more . then , <br> P(choosing a carton having defective bulbs 6 or more ) <br> `P (E_(4))` <br> = `("number of cartons having defective bulbs 6 or more")/("total number of cartons")` <br> `= (5 + 2)/(700) = (7)/(700) = (1)/(100) = 0.01.`